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3 years ago

A polyhedron with 16 edges cannot be a prism. Explain why this must be true

Mathematics

1 answer:

Readme [11.4K]3 years ago

3 0

Answer:

This prism has: 5 Faces. 6 Vertices (corner points) 9 Edges.

Step-by-step explanation:

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Does anybody know this answer

yuradex [85]

Answer:

its 90

Step-by-step explanation:

beacuse it is

4 0

3 years ago

Read 2 more answers

Tito bought a baseball card for $24.00 and sold it for $37.00. what is the percent of increase rounded to the nearest tenth?

ladessa [460]

Answer: Option 'b' is correct.

Step-by-step explanation:

Since we have given that

Cost price of a baseball card = $24

Selling price of a baseball card = $37

So, Profit would be

$37-24=\$13$

So, Profit % would be

$\dfrac{13}{24}\times 100\\\\=54.16\%\\\\\approx 54.2\%$

Hence, Option 'b' is correct.

6 0

3 years ago

Read 2 more answers

Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall f

spin [16.1K]

Answer:

Part 1) 0.50 inches

Part 2) 1.14 inches

Part 3)

a) 1.25 inches

b) -0.32 inches

Step-by-step explanation:

The complete question in the attached figure

Part 1) Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall for the last June

Let

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

The difference between the average rainfall and the actual rainfall for the last June is given by the expression

$(x-y)$

we have

$x=0.67\ in\\y=0.17\ in$

substitute

$0.67-0.17=0.50\ in$

Part 2) The departure from the average rainfall last July was -0.36 inches. How much rain fell last July?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

$D=y-x$

we have

$D=-0.36\ in\\x=1.5\ in$

substitute the given values

$-0.36=y-1.5$

solve for y

$y=1.5-0.36\\y=1.14\ in$

Part 3)

<u>Part a)</u> How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

<u>Part b</u>) What would the departure from the average be in August in that

situation?

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Find the average rainfall for these three months

Adds the average rainfall and divide by 3

$(0.67+1.5+1.57)/3=1.25\ in$

Part b) What would the departure from the average be in August in that

situation?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

$D=y-x$

we have

$x=1.57\ in\\y=1.25\ in$

substitute the given values

$D=1.25-1.57=-0.32\ in$

7 0

4 years ago

Water flows through pipe at a rate of 490 Milliliters every 6.5 hours express this rate of flow influence one's permanent round

likoan [24]

Answer:

To the nearest hundredth, the rate of flow will be 75.38 mm/hr

Step-by-step explanation:

Here in this case, we are to express the rate at which the water flow and round it up to the nearest hundredth.

We are told that water flows through the pipe at a rate of 490 mm every 6.5 hours.

Now, the rate will be 490/6.5 = 75.384615384615 mm/hr

Rounding this value to the nearest hundredth, we have 75.38 mm/hr

7 0

3 years ago

ALGEBRA

riadik2000 [5.3K]

Is there a picture that I can see so I can hopefully help you out?

7 0

2 years ago