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krok68 [10]
3 years ago
9

How many times smaller is 2 × 10^-10 than 4 × 10^-5

Mathematics
1 answer:
natta225 [31]3 years ago
7 0

Answer:

200,000

Step-by-step explanation:

To find how many times smaller is smaller number than greater number, divide greater number by smaller number.

Greater number =4\times 10^{-5}

Smaller number =2\times 10^{-10}

Then

\dfrac{\text{Greater number}}{\text{Smaller number}}\\ \\=\dfrac{4\times 10^{-5}}{2\times 10^{-10}}\\ \\=\dfrac{4}{2}\times \dfrac{10^{-5}}{10^{-10}}\\ \\=2\times \dfrac{1}{10^{-5}}\\ \\=2\times 10^5\\ \\=2\times 100,000\\ \\=200,000

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I found the complete question on Chegg, here is the full question:

Write the restrictions that should be imposed on the variable for each of the following function. Then find, explicitly, the domain for each function and write it in the interval notation a) f(x)=(x-2)/(x-1)  b) g(p)=√(1-2p)  c) m(s)= (s^2+4s+4)/√(s+1)

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Learn more about square root here:

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