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3 years ago

What does -8(6x - 2) equal? How do I get my answer?

Mathematics

2 answers:

Free_Kalibri [48]3 years ago

7 0

Answer:

-48x+16

Step-by-step explanation:

-8(6x - 2) first multiply each term in the parentheses by 8 to get -8x6x-8x(-2) and calculate the product to get your answer which is -48x+16

il63 [147K]3 years ago

4 0

Answer:

-48x + 16

Step-by-step explanation:

Multiply - 8 times 6x

Answer - 48 (negative times positive equals a negative)

Multiply - 8 times - 2

Answer - 16 (negative times a negative equals a positive)

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lapo4ka [179]

Answer:

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Step-by-step explanation:

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3 years ago

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7.75 as fraction or mixed number

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3 years ago

A cereal mixture contains Almond, Wheat, and Corn in the ratio of 3:5:7. What amount of this mixture contains 9 kilograms of Alm

Mice21 [21]

The total cereal mixture is 45 kilograms

Solution:

Given that, cereal mixture contains Almond, Wheat, and Corn in the ratio of 3:5:7

Therefore,

Almond : Wheat : Corn = 3 : 5 : 7

Let the almond present be 3x

Let the wheat present be 5x

Let the corn present be 7x

Therefore,

Total cereal mixture = 3x + 5x + 7x

Total cereal mixture = 15x

Given that mixture contains 9 kg of almond

Almond = 9

We know that,

Almond present = 3x

3x = 9

x = 3

Therefore,

Total cereal mixture = 15x = 15(3) = 45

Thus total cereal mixture is 45 kilograms

3 0

4 years ago

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.