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Ostrovityanka [42]
2 years ago
7

5 of 10

Computers and Technology
1 answer:
DaniilM [7]2 years ago
3 0

Answer:

what

Explanation:

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Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress 50%, or 2 sec
kozerog [31]

Answer: bandwidth = 0.10 MB/s

Explanation:

Given

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.50 MB / Bandwidth)

Transfer Size = 0.50 MB

Total Time = Compression Time + RTT + (0.50 MB /Bandwidth)

Total Time = 1 s + RTT + (0.50 MB / Bandwidth)

Compression Time = 1 sec

Situation B:

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.40 MB / Bandwidth)

Transfer Size = 0.40 MB

Total Time = Compression Time + RTT + (0.40 MB /Bandwidth)

Total Time = 2 s + RTT + (0.40 MB / Bandwidth)

Compression Time = 2 sec

Setting the total times equal:

1 s + RTT + (0.50 MB / Bandwidth) = 2 s + RTT + (0.40 MB /Bandwidth)

As the equation is simplified, the RTT term drops out(which will be discussed later):

1 s + (0.50 MB / Bandwidth) = 2 s + (0.40 MB /Bandwidth)

Like terms are collected:

(0.50 MB / Bandwidth) - (0.40 MB / Bandwidth) = 2 s - 1s

0.10 MB / Bandwidth = 1 s

Algebra is applied:

0.10 MB / 1 s = Bandwidth

Simplify:

0.10 MB/s = Bandwidth

The bandwidth, at which the two total times are equivalent, is 0.10 MB/s, or 800 kbps.

(2) . Assume the RTT for the network connection is 200 ms.

For situtation 1:  

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 1 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.50 MB

Total Time = 1.2 sec + 5 sec

Total Time = 6.2 sec

For situation 2:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 2 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.40 MB

Total Time = 2.2 sec + 4 sec

Total Time = 6.2 sec

Thus, latency is not a factor.

5 0
2 years ago
1. Which of the following is not related to a buffer overflow? A. Static buffer overflow B. Index error C. Canonicalization erro
GaryK [48]

Answer: C) Canonicalization error

Explanation:

Canonicalization error is the error or fault that occurs when data is changed into canonical form or standard form that persist different representation.This can create fault when different filenames or structure is assigned to data and canonization cannot take place as it works for simple data representation.

  • Other options are incorrect because static buffer flow is stable writing or reading of data that reaches outside the buffer boundary.Index error is accessing of index by any user that is found beyond the index's list boundary.
  • Heap overflow is the stack gets overlowed outside the boundary while overwriting heap.Thus, the correct option is option(C).
4 0
2 years ago
What are the basic tools for coding HTML manually?
Dimas [21]
The answer should be C, you need a text editor to write out the code, and then a web browser to view what the code creates.
8 0
2 years ago
Read 2 more answers
What is the term for the error caused when one end of an unshielded twisted-pair (UTP) cable is terminated in the T568A configur
FinnZ [79.3K]

Answer:

A transposition is the correct answer.

Explanation:

A transposition is the type of encryption that caused when one side of the unshielded twisted pair cable is finished in the configuration of  T568A and at the other side of the configuration of T568B, it is also termed as error or cipher. So, that's why the following answer is true.

7 0
2 years ago
. When attempting to minimize memory usage, the most efficient way to do group processing when using the MEANS procedure is to u
MrRissso [65]

Answer:

A. the BY statement.

Explanation:

The BY statement aids the procedure MEANS to develop the tree for the current BY group only, thereby analyze the stats, and clean the tree prior to the start and development of the next BY group.

However, without the BY statement, procedure MEANS develops its AVL tree for both the whole file and all sector estimates crossings established in CLASS.

Hence, in this case, the correct answer is the BY Statement.

8 0
3 years ago
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