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2 years ago

Explain why it was important for scientists to have a standard system of naming compounds and other chemical procedures.

2 answers:

6 0

He primary function of chemical nomenclature is to ensure that a spoken or written chemical name leaves no ambiguity concerning which chemical compound the name refers to: each chemical name should refer to a single substance. The form of nomenclature used depends on the audience to which it is addressed.

Minchanka [31]2 years ago

5 0

It is important for scientists to have a standard system of naming compounds and other chemical procedures to avoid ambiguity in the nomenclature of chemical compounds and procedures.

Chemicals may be referred to by various names among various scientists in different places. These different names creates confusion when scientists present their discoveries to other scientists outside their locality.

Therefore, it is imperative that a unified and standard system of nomenclature should be devised so that all scientists can have the same name for compounds. This reduces ambiguity associated with the nomenclature of chemical substances and procedure.

Learn more: brainly.com/question/1157188

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how will you seperate dye from black ink? draw a neatly labelled same?? fast I will mark brainly 100%

Nonamiya [84]

Answer:

put it through a distillery

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3 years ago

Beta particles cannot penetrate very far into solids because they _____.

givi [52]

Answer: Beta particles cannot penetrate very far into solids because they have no mass.

Reason:
Penetrating power of particle depending upon the velocity and mass of particle. Greater the mass and velocity. Higher will be the penetrating power. In case of Beta particles, they are electrons. Mass of an electron is 9.1 X $10^{-31}$ Kg. Due to such negligible mass, they have very low penetrating power.

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3 years ago

Read 2 more answers

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som

irinina [24]

Answer:

$m_{KBr}=6.030gKBr$

Explanation:

Hello.

In this case, since the normal boiling point of X is 117.80 °C, the boiling point elevation constant is 1.48 °C*kg*mol⁻¹, the mass of X is 100 g and the boiling point of the mixture of X and KBr boils at 119.3 °C, we can use the following formula:

$(T_b-T_b_0)=i*m*K_b$

Whereas the Van't Hoff factor of KBr is 2 as it dissociates into potassium cations and bromide ions; it means that we can compute the molality of the solution:

$m=\frac{T_b-T_b_0}{i*K_b}=\frac{(119.3-117.8)\°C}{2*1.48\°C*kg*mol^{-1}}\\ \\m=0.507mol/kg$

Next, given the mass of solventin kg (0.1 kg from 100 g), we compute the moles KBr:

$n_{KBr}=0.507mol/kg*0.1kg=0.0507mol$

Finally, considering the molar mass of KBr (119 g/mol) we compute the mass that was dissolved:

$m_{KBr}=0.0507mol*\frac{119g}{1mol} \\\\m_{KBr}=6.030gKBr$

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3 years ago

An unknown element, x, reacts with rubidium to form the compound rb2x. in other compounds this element also can accommodate up t

SVETLANKA909090 [29]

There are few elements that can form 12 electron rather than the usual 8. Therefore these are the possible answers:

Sulfur = 2Na + S --> Na2S 
Selenium = 2Na + Se --> Na2Se
Tellurium = 2Na + Te --> Na2Te

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2 years ago

Why Al is a member of group 13 rather than group 3?

Levart [38]

Answer:

Boron and Aluminium

Explanation:

Boron and Aluminium are present in Group 13 of the modern periodic table. Group 13 (IUPAC System) can also be referred to as Group III-A. Logically, Boron and Aluminum can't be placed alongwith elements such as Yttrium as they don't exhibit properties of a transition metal.

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3 years ago