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yarga [219]
3 years ago
9

2,631 dividido entre 24

Mathematics
1 answer:
Ivan3 years ago
5 0

Answer:

2631 divided by 24 = 109.625

Step-by-step explanation:

The result of 2631/24 is a terminating decimal with 3 digits to the right of the decimal point.

2631 divided by 24 in decimal = 109.625

2631 divided by 24 in fraction = 2631/24

2631 divided by 24 in percentage = 10962.5%

Note that you may use our state-of-the-art calculator above to obtain the quotient of any two integers or decimals, including 2631 and 24, of course.

Repetends, if any, are denoted in ().

The conversion is done automatically once the nominator, e.g. 2631, and the denominator, e.g. 24, have been inserted.

SPANISH:

El resultado de 2631/24 es un decimal final con 3 dígitos a la derecha del punto decimal.

2631 dividido por 24 en decimal = 109,625

2631 dividido por 24 en fracción = 2631/24

2631 dividido por 24 en porcentaje = 10962,5%

Tenga en cuenta que puede utilizar nuestra calculadora de última generación anterior para obtener el cociente de dos enteros o decimales cualesquiera, incluidos 2631 y 24, por supuesto.

Los repetends, si los hay, se indican en ().

La conversión se realiza automáticamente una vez que el nominador, por ejemplo, 2631, y el denominador,

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A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

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A bike store sells scooters at a 54% markup. If the store bought each scooter for $29.25, what is the resale price to the neares
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The purchasing price of the store = $29.25.

They want to resale it at 54% markup of the purchasing price.

54% of 29.25 = 0.54 × 29.25.

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Resale price = The purchasing price + Markup

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On adding 29.25 and 15.795, we get 45.045.

We can round it to 45 to the nearest dollar.

<h3>Therefore, the resale price to the nearest dollar is $45.</h3>
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