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ddd [48]
3 years ago
14

Helppppppppppppppppppppppppppppppppppppppppp pls

Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0

Answer:

Coffee Beans to Go is cheaper, selling coffee at $4.75 per pound.

Step-by-step explanation:

The graph is cruddy and hard to see but! when you go to 2 pounds and then up the the cost, it's $9.50. 9.50/2= 4.75. kapeesh??

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Write 8.12 as a mixed number in simplest form.<br> (It’s a repeating decimals
kicyunya [14]

Answer:

8 3/25 because 8.12 is 8 12/100 and when you simplify 12/100 you get 3/25

8 0
3 years ago
What is 23/6 as a mixed number
ludmilkaskok [199]
The answer is 3 and 5/6 because 6 goes into 23 3 times with 5 left over. then you put the five over the denominator 6. make sense dear?
7 0
3 years ago
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How would u write 64 square centimeters?Also for my problem would I put 70 feet or 70 square feet?
Leto [7]
64cm2 but make the number two small and in the corner of the m
70 square feet
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3 years ago
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Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos &#10;y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
X + y = -3 &amp; 5x - 2y = -50 ELIMINATION
Karolina [17]
I gotchu luh bro....

7 0
3 years ago
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