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34kurt
3 years ago
14

Please help me with this geometry problem!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Vilka [71]3 years ago
6 0
It totals out to 2496 in^2
Hope this helped

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((PLEASE ANSWER WITH A B C or D))
natali 33 [55]

Answer:

  D.  60°

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that the relationship of interest is ...

  Sin = Opposite/Hypotenuse

  sin(M) = ON/OM = 4(√3)/8 = (√3)/2

  M = sin⁻¹((√3)/2) = 60°

8 0
2 years ago
What is the value of x will mark brain list  20 extra points
miskamm [114]
Its an equilateral triangle so all sides are equal.

2x + 5 = 4x - 1
5 = 2x - 1
6 = 2x
3 = x

Do you get it?
4 0
2 years ago
What is the surface area of the figure made from this net?
LekaFEV [45]
Let's work on Sections. The top rectangle has an area of 54 (6x9) the base rectangle has an area of 360 ((9+6+9+5)×12) and the bottom rectangle has an area of 54 (9×6) now we add and we get 468. thus the answer is C.

6 0
2 years ago
Find the remainder when 1 + 2 + 2^2 + 2^3 + ... + 2^100 is divided by 7.<br><br> Thanks in advance!
Firlakuza [10]

Answer:

3.

Step-by-step explanation:

This is a geometric series so the sum is:

a1 * r^n - 1 / (r - 1)

= 1 * (2^101 -1) / (2-1)

= 2^101 - 1.

Find the remainder when 2^101 is divided by 7:

Note that 101 = 14*7 + 3 so

2^101 = 2^(7*14 + 3) =  2^3  * (2^14)^7 = 8 * (2^14)^7.

By Fermat's Little Theorem  (2^14) ^ 7 = 2^14 mod 7 = 4^7 mod 7.

So 2^101 mod 7 = (8 * 4^7) mod 7

                           = (8 * 4) mod 7

                            = 32 mod 7

                            = 4 = the remainder when 2^101 is divided by 7.

So the remainder when 2^101- 1 is divided by 7 is 4 - 1 = 3..

4 0
2 years ago
Gina has 1200 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed ar
Alekssandra [29.7K]
We know the perimeter formula would be 1200=2x+2y. And the area will be A=x*y
We can to take the derivative of the area formula to find where it is a max but we must first substitute something in from the first formula so we only have one variable.

1200-2x=2y
600-x=y

A=(x)*(600-x)
A=600x-x^2

Now we take the derivative:
A'=600-2x (set equal to 0 and solve)
0=600-2x
2x=600
x=300 

Then when we plug this into the perimeter formula, we can solve for y
1200=2x+2y
1200=2(300)+2y
1200=600+2y
600=2y
y=300

So both the length and width are 300 yards, and the area would be 90,000 square yards

Hope this helps
8 0
3 years ago
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