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sukhopar [10]
3 years ago
14

How do I solve this equation?

Mathematics
1 answer:
Anon25 [30]3 years ago
6 0

Answer:

By doing process by process

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What is 3/4 x 2? I tried getting it, but my teacher said it was wrong
Karolina [17]
3/4 x 2/1 = 6/4

Simplify:

6/4 = 3/2

So, 3/2 or 1.5
7 0
3 years ago
Which angle is supplementary to DFA?​
lisabon 2012 [21]

Answer:

<AFB

Step-by-step explanation:

Supplementary angles are the angles that's sum up to 180° which is called a straight angle.

In this question we see AFB is supplementary to DFA for DFB is the straight angle.

6 0
3 years ago
To speed the process of surveying, surveyors use brass metal plates to record important information. The benchmarks, as they are
Agata [3.3K]

Answer:

Feet Above Sea Level

Step-by-step explanation:

A benchmark is a term in Surveying and Geo informatics, that describes a point of reference established at a known elevation which serves as basis in which other elevation or topographical point can be measured.

Therefore, when determining the benchmark, it's height is calculated relative to the vertical datum of the area, typically mean sea level, which is then recorded in FEET ABOVE SEA LEVEL.

Hence, Benchmarks measurements refer to FEET ABOVE SEA LEVEL.

5 0
3 years ago
PLZ SHOW ALL WORK
lara31 [8.8K]

Part I
We have the size of the sheet of cardboard and we'll use the variable "x" to represent the length of the cuts. For any given cut, the available distance is reduced by twice the length of the cut. So we can create the following equations for length, width, and height.
width:  w = 12 - 2x
length: l = 18 - 2x
height: h = x

Part II
v = l * w * h
v = (18 - 2x)(12 - 2x)x
v = (216 - 36x - 24x + 4x^2)x
v = (216 - 60x + 4x^2)x
v = 216x - 60x^2 + 4x^3
v = 4x^3 - 60x^2 + 216x

Part III
The length of the cut has to be greater than 0 and less than half the length of the smallest dimension of the cardboard (after all, there has to be something left over after cutting out the corners). So 0 < x < 6

Let's try to figure out an x that gives a volume of 224 in^3. Since this is high school math, it's unlikely that you've been taught how to handle cubic equations, so let's instead look at integer values of x. If we use a value of 1, we get a volume of:
v = 4x^3 - 60x^2 + 216x
v = 4*1^3 - 60*1^2 + 216*1
v = 4*1 - 60*1 + 216
v = 4 - 60 + 216
v = 160

Too small, so let's try 2.
v = 4x^3 - 60x^2 + 216x
v = 4*2^3 - 60*2^2 + 216*2
v = 4*8 - 60*4 + 216*2
v = 32 - 240 + 432
v = 224

And that's the desired volume.
So let's choose a value of x=2.
Reason?
It meets the inequality of 0 < x < 6 and it also gives the desired volume of 224 cubic inches.
3 0
3 years ago
178 rounded to the nearest hundred
Reika [66]
In order to round to the nearest 100 you look at the 10s place.

It's 7 which means we round up. So 178 rounded to the nearest 100 is 200.<span />
6 0
3 years ago
Read 2 more answers
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