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fiasKO [112]
2 years ago
7

The price of Stock A at 9 A.M. was ​$14.65. Since​ then, the price has been increasing at the rate of ​$0.13 each hour. At noon

the price of Stock B was ​$15.40. It begins to decrease at the rate of ​$0.12 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?
Mathematics
2 answers:
egoroff_w [7]2 years ago
8 0

Answer:

three hours

Step-by-step explanation:

stock A would be at 14.65+0.13+0.13+0.13=15.04

stock B would be at 15.40-0.12-0.12-0.12=15.04

Nataly [62]2 years ago
5 0

Answer:

The prices of the two stocks will be the same in 1.56 hours.

 

The price of Stock A at 9 A.M. was ​$12.95 Since​ then, the price has been increasing at the rate of ​$0.12 each hour.

This means that after x hours, the value of Stock A is:

After noon:

Noon is 3 hours after 9 AM, so

So in x hours after noon, the value is given by:

At noon the price of Stock B was ​$13.70. It begins to decrease at the rate of ​$0.13 each hour.

This means that after x hours, the value of Stock B is:

In how many hours will the prices of the two stocks be the​ same?

This is x for which:

The prices of the two stocks will be the same in 1.56 hours.

Step-by-step explanation:

Hope this helps:)

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