All categories

3 years ago

What is the solution of 3b² = 27c² + 9 = 9

Mathematics

2 answers:

Tresset [83]3 years ago

6 0

Step-by-step explanation:

$And \: second \: one \: answer \: is \: 0.$

Papessa [141]3 years ago

4 0

Answer:

Step-by-step explanation:whole divide it

3b^=27

b^=27/3

b^=9

take squre roote

b=3

You might be interested in

Which shows the proper use of the distributive property

Karo-lina-s [1.5K]

Answer:

-2 (6x - y) = -12x + 2y

Step-by-step explanation:

By using the distributive property, you start by multiplying -2 and 6x which gets you -12x. You then multiply -2 and -y (in other words -y = -1y) so, -2* -y would get you 2 as a negative multiplied by a negative is a positive. So, adding them together would get your final answer: -2 (6x - y) = -12x + 2y

5 0

3 years ago

Which of the following could be the ratio between the lengths of the two legs of a 30-60-90 triangle?

Artist 52 [7]

Answer:c

options A and B

Step-by-step explanation:

the ratio between the lengths of the two legs of a 30-60-90 triangle

General ration of 30-6- 90 degrees triangle is

x : xsqrt(3) : 2x

When x=1 the ratio becomes 1 : 1 sqrt(3)

when x= 2sqrt(3) the ratio becomes

It becomes

Two sides of 30-60-90 triangle cannot be equal

so option c and option D are not possible

sqrt(2) is also not possible because we have sqrt(3) in general ratio

PLS MARK ME AS BRAINLIEST.

5 0

2 years ago

Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n

aliya0001 [1]

Answer:

$f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}$

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

$f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...$

We first compute the n-th derivative of $f(x)=\ln(1+2x)$ , note that

$f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\$

Now, if we compute the n-th derivative at 0 we get

$f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!$

and so the Maclaurin series for f(x)=ln(1+2x) is given by

$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

3 0

3 years ago

Which expression is equivalent to is m4?<br> m2+m3<br> m1+m2<br> m1+m3<br> m5+ m6

Airida [17]

Answer: m1+m3

Step-by-step explanation: 1+3=4 and m1+m3 has the same varibles in the expression.

8 0

3 years ago

If q/18 = 5 what does q = to

qaws [65]

Answer:

Q= 90

Step-by-step explanation:

To do this problem you need to get q by itself and to do that you would move the 18 over

When you move the 18 over however you need to multiply and you will get 90

When ever you want to get a variable by itself always remember to switch the sign so if it was positive then switch it to negative and vice versa. It will also apply to multiplication and division just like this one

7 0

3 years ago

Read 2 more answers

What is the solution of 3b² = 27c² + 9 = 9​

What is the solution of 3b² = 27c² + 9 = 9