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Akimi4 [234]
3 years ago
7

What is the solution of 3b² = 27c² + 9 = 9​

Mathematics
2 answers:
Tresset [83]3 years ago
6 0

Step-by-step explanation:

And \:  second  \: one  \: answer  \: is \:  0.

Papessa [141]3 years ago
4 0

Answer:

Step-by-step explanation:whole divide it

3b^=27

b^=27/3

b^=9

take squre roote

b=3

c^

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A 600-ft tall building is represented by a 30-in. tall model.
alexdok [17]

\huge\boxed{19\ \text{inches}}

First, find the scale factor by dividing the first building's real-life height by its model height.

\frac{600}{30}=\frac{60}{3}=20

Now, we'll write an equation to find the model height of the second building.

r=20m

Here is an equation where r represents the real-life height of a building, 20 represents the scale factor, and m represents the model height of the same building.

Fill in the information we already know.

380=20m

Divide both sides by 20.

\frac{380}{20} = \frac{20m}{20}

\large{\boxed{19}}=m

So, the model height of the second building is 19 inches.

5 0
3 years ago
An image of a book shown on a website is 1.5 inches wide and 3 inches tall on a conputer monitor the actual book is 9 inches wid
torisob [31]

Answer:

Step-by-step explanation:

Step one: 9÷1.5= 6

Step two: 3·6=18

The actual book is 18 inches tall and 9 inches wide

7 0
4 years ago
ALGEBRA 1, SEM. 2
grigory [225]
2•(1/4)^(2-1)= 2•(1/4)= 1/2
2•(1/4)^(3-1)= 2• (1/4)^2 = 2•1/16=1/8
3 0
4 years ago
5x + 50 = 100<br> What is x?
vfiekz [6]

Answer:

x = 10

Step-by-step explanation:

5x + 50 = 100

=> 5x = 100 - 50

=> 5x = 50

=> x = 10

Hoped this helped.

8 0
3 years ago
A simple random sample of 60 households in city 1 is taken. In the sample, there are 45 households that decorate their houses wi
murzikaleks [220]

Answer:

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0: p1= p2 there is no difference in population proportions of households that decorate their houses with lights for the holidays

against Ha : p1≠ p2  (claim)  ( two sided)

The significance level is set at ∝= 0.05

The critical value for two tailed test at alpha=0.05 is ± 1.96

or Z∝= 0.05/2= ± 1.96

The test statistic is

Z = p1-p2/√pq(1/n1 +1/n2)

p1= proportions of households  decorating in city 1  = 45/60=0.75

p2= proportions of households  decorating in city 2 = 40/50= 0.8

p = the common proportion on the assumption that the two proportion are same.

p =   \frac{n_1p_1 +n_2p_2}{n_1+n_2}

Calculating

p =60 (0.75) + 50 (0.8) / 110

p=  45+ 40/110= 85/110 = 0.772

so  q = 1-p= 1- 0.772= 0.227

Putting the values in the test statistic and calculating

z= 0.75- 0.8/ √0.772*0.227( 1/60 + 1/50)

z= -0.05/√ 0.175244 ( 110/300)

z= -0.05/0.25348

z= -0.197

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

4 0
3 years ago
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