How do you find the vertex of a parabola..?
2 answers:
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Answer:
see explanation
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h. k) are the coordinates of the vertex and a is a multiplier
here (h, k) = (- 6, - 1), thus
y = a(x + 6)² - 1
To find a substitute one of the roots into the equation
Using (- 3, 0), then
0 = a(- 3 +6)² - 1
0 = 9a - 1 ( add 1 to both sides )
1 = 9a ( divide both sides by 9 )
a = , thus
y = (x + 6)² - 1 ← in vertex form
Expand factor and simplify
y = (x² + 12x + 36) - 1 ← distribute
y = x² +
x + 4 - 1
= x² +
x + 3 ← in standard form
The image is attached with answer
<h3>What is a Quadrilateral ?</h3>
A quadrilateral is a polygon with four sides , four angles and four vertices.
It is given in the question that
Quadrilateral BGTS has vertices B (-3, 4), G (-1, 3), T (-1, 1), and S (-4, 2).
A graph has to be drawn of
its image after a translation along (5,0) and a reflection in the x-axis.
The coordinates after translation and reflection is is B (8, -4), G (6, -3), T (6, -1), and S (7, -2).
The image is attached with the answer .
To know more about Quadrilateral
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