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elena-14-01-66 [18.8K]
3 years ago
5

How do you find the vertex of a parabola..?

Mathematics
2 answers:
Tasya [4]3 years ago
4 0
Well you would have to use the formula x= -b/2a to find the value of x and then substitute that value of x in the equation to find y<span />
11111nata11111 [884]3 years ago
4 0
The vertex formula is derived from the completing-the-square process, just as is the Quadratic Formula. In each case, memorization is probably simpler than completing the square.) For a given quadratic y = ax2 + bx + c, the vertex (h, k) is found by computing h = –b/2a, and then evaluating y at h to find k.
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3 years ago
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GuDViN [60]

Answer:

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Hope this helps

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Step-by-step explanation:

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3 years ago
Write the equation for a parabola with a focus at (6,-4) and a directrix at y= -7
shtirl [24]

Given:

The focus of the parabola is at (6,-4).

Directrix at y=-7.

To find:

The equation of the parabola.

Solution:

The general equation of a parabola is:

y=\dfrac{1}{4p}(x-h)^2+k                  ...(i)

Where, (h,k) is vertex, (h,k+p) is the focus and y=k-p is the directrix.

The focus of the parabola is at (6,-4).

(h,k+p)=(6,-4)

On comparing both sides, we get

h=6

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Directrix at y=-7. So,

k-p=-7                            ...(iii)

Adding (ii) and (iii), we get

2k=-11

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Putting k=-5.5 in (ii), we get

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p=-4+5.5

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Putting h=6, k=-5.5,p=1.5 in (i), we get

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y=\dfrac{1}{6}(x-6)^2-5.5

Therefore, the equation of the parabola is y=\dfrac{1}{6}(x-6)^2-5.5.

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2 years ago
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<h3>Properties of Soil</h3>

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Read more on properties of soil;

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