suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z =
=
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Let's firstly convert the mixed fraction to "improper" and then proceed,
First solve for 16x20. 16*20= 320 inches. Now subtract the area that is removed, the 8x8 square. 8*8=64. 320-64=256. Our answer is 256in^2.
Answer:
The car is going at 8.125 m/s²
Step-by-step explanation:
Answer:
eleven and three hundredths.
Step-by-step explanation: