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Tcecarenko [31]
2 years ago
13

Can you help me with this problem? Its for my PreCalculus class.​

Mathematics
1 answer:
Ivanshal [37]2 years ago
7 0

(X^4 - 3X^3 - 17X^2 - 3X - 60)
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Solve for a in terms of b and c:3a+4b=c
MariettaO [177]
We want a in terms of b and c:     <span>3a+4b=c

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Divide all terms by 3:

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8 0
3 years ago
A ball rolls down an inclined plane such that the distance (in centimeters) that it rolls in t seconds is given by s(t) = 2t^3 +
IRISSAK [1]
The ball's velocity will be represented by the derivative of its distance function:

s'(t)=6t^2+6t

Now find the times t for which this is equal to 30, i.e. solve

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This has two solutions, t=-\dfrac{1\pm\sqrt{21}}2, but only one is positive and falls in the interval [0,3]. So the velocity reaches 30 cm/s when t=-\dfrac{1-\sqrt{21}}2\approx1.79.
3 0
3 years ago
What fraction is equal to the decimal 0.32?<br><br> Enter your answer in the box in simplest form.
AVprozaik [17]

The answer is 8/25 I believe


3 0
3 years ago
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Delicious77 [7]

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5 0
3 years ago
The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice
777dan777 [17]
If period of f(\theta) is one-half the period of g(\theta) and
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To find the period of sine function f(\theta)=asin(b\theta+c) we use the rule T_{f}= \frac{2\pi}{b}.
<span /><span />
f is sine function where f (0)=0, then c=0; with period \pi, then f(\theta)=asin 2\theta, because T_{f}= \frac{2 \pi }{2} = \pi. 

To find a we consider the condition f( \frac{ \pi }{4} )=4, from where asin2* \frac{\pi}{4} =a*sin \frac{ \pi }{2} =a=4.

If the amplitude of f(\theta) is twice the amplitude of g(\theta) , then g(\theta) has a product factor twice smaller than f(\theta) and while period of g(\theta)<span> </span> is 2π and g(0)=0, we can write g(\theta)=2sin\theta.






8 0
3 years ago
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