2 years ago

Can you help me with this problem? Its for my PreCalculus class.

Mathematics

1 answer:

Ivanshal [37]2 years ago

7 0

(X^4 - 3X^3 - 17X^2 - 3X - 60)

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Match each expression in the left column with the correct product in the right column.

lesya692 [45]

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Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

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3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

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$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

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3 years ago

Which number would be an element of the set of integers but not an element of the set of whole numbers,0, -3, 5, -1/2?

iren [92.7K]

Integers are negative or positive whole numbers
whole numbers do not include negatives

so ur answer is -3...it is considered an integer, but not a whole number

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3 years ago

Can you help me with this problem? Its for my PreCalculus class.​

Can you help me with this problem? Its for my PreCalculus class.