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Maurinko [17]
3 years ago
6

1. There is no formation of volcanoes in the convergence between

Chemistry
1 answer:
tester [92]3 years ago
5 0

A volcano is caused by a rupture in the crust from which molten magma

escapes

The correct options are;

  1. B. Two continental plates
  2. C. Volcanoes
  3. C. A tsunami in the ocean
  4. C. The temperature in the mantle is higher than in the crust
  5. A. Volcanic island arcs
  6. A. Earthquake
  7. B. Trench
  8. C. Subduction
  9. A. Fault
  10. C Tsunami
  11. A. Convergent plate boundary
  12. See attached drawing (<em>Based on Department of Education Science Module)</em>
  13. D. a, b and c
  14. C. Converging oceanic plates
  15. It is where the oceanic plates subduct under the continental plate

Reasons:

1. Due to the equal densities and buoyancy of the plates, there is no

subduction and the plates rise to form mountain ranges and no volcanoes.

2. The subduction causes the plates to form magma and then volcanoes.

3. Shallow earthquakes that have their epicenter at the fault line in the

ocean generate a tsunami.

4. The mantle lay under each plate and therefore, the high temperatures

of the mantle does not support the fact.

5. Volcanic arcs are formed in the convergence of two oceanic or oceanic

and continental plates.

6. When two continental plates converge, shallow earthquakes occur.

7. A crack called a trench is formed by the interaction of an oceanic crust

and another crust.

8. A subduction occurs when oceanic plates converge.

9. A fault is produced by horizontal plate movement.

10. A Flip or kick upwards of water is known as a tsunami.

11. Subduction occurs during convergence of two plates such that a

subducted plate goes down beneath an overriding plate.

12. The illustration of seafloor spreading consists of two plates moving

away from each other.

<em>Question 12: Based on Department of Education Science Module</em>.

<em />

13. Earthquake occur at places where the plates are moving (including

subducting).

14. Volcanic island arcs are formed by two oceanic plates.

15. At the location where the continents meet the seas, oceanic plates are

subducted under the continental plate, melted to magma in the mantle

from which volcano is formed.

Learn more about volcanoes here:

brainly.com/question/19424796

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A 1.00 kg sample of Sb2S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium,
Scorpion4ik [409]

<u>Answer:</u> The value of K_c is coming out to be 0.412

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For Sb_2S_3</u>

Given mass of Sb_2S_3 = 1.00 kg = 1000 g   (Conversion factor: 1 kg = 1000 g)

Molar mass of Sb_2S_3 = 339.7 g/mol

Putting values in equation 1, we get:

\text{Moles of }Sb_2S_3=\frac{1000g}{339.7g/mol}=2.944mol

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 10.0 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol

  • <u>For hydrogen sulfide:</u>

Given mass of hydrogen sulfide = 72.6 g

Molar mass of hydrogen sulfide = 34 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrogen sulfide}=\frac{72.6g}{34g/mol}=2.135mol

The chemical equation for the reaction of antimony sulfide and hydrogen gas follows:

                  Sb_2S_3(s)+3H_2(g)\rightarrow 2Sb(s)+3H_2S(g)

Initial:            2.944      5

At eqllm:      2.944-x     5-3x         2x        3x

We are given:

Equilibrium moles of hydrogen sulfide = 2.135 moles

Calculating for 'x', we get:

\Rightarrow 3x=2.135\\\\\Rightarrow x=\frac{2.135}{3}=0.712

Equilibrium moles of hydrogen gas = (5 - 3x) = (5 - 3(0.712)) = 2.868 moles

Volume of the container = 25.0 L

Molarity of a solution is calculated by using the formula:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}

The expression of K_c for above equation, we get:

K_c=\frac{[H_2S]^3}{[H_2]^3}

The concentration of solids and liquids are not taken in the expression of equilibrium constant.

K_c=\frac{(\frac{2.135}{25})^3}{(\frac{2.868}{25})^3}\\\\K_c=0.412

Hence, the value of K_c is coming out to be 0.412

3 0
3 years ago
assuming gasoline can be represented as C8H18, how much oxygen is needed to completely burn this fuel. answer in grams of oxygen
aleksandrvk [35]

Answer:

3.51 g of oxygen per gram of gasoline is required.

Explanation:

Solution:

First of all we will write the balance chemical equation.

C8H18 + 12.5O2 → 8CO2 + 9H2O

This equation shows that,

1 mole of gasoline react with 12.5 mole of oxygen for complete burning.

mass of one mole of gasoline = 8×12 + 18×1 = 114 g

mass of 12.5 mole of oxygen = 12.5 (16×2) = 400 g

Formula:

mass of oxygen per gram of gasoline = (400 / 114) = 3.51

so, 3.51 g of oxygen require for per gram of gasoline.

5 0
4 years ago
Write a balanced equation for the combustion of gaseous methane (CH4), a majority component of natural gas, in which it combines
max2010maxim [7]

Answer:

CH₄(g) + 2O₂(g) ---> 1CO₂(g) + 2H₂O(g)

Explanation:

any combustion of a hydrocarbon equation is in form:

CₓHₐ(g) + BO₂(g) ---> YCO₂(g) + ZH₂O(g), where x,a,b,y,z are all whole number positive integers

there will be 1 CO₂ to 2 H₂O, since there is 1 C to 4 H in CH₄; it is not 1:4 since 2 H is needed in H₂O

CH₄(g) + _O₂(g) ---> 1CO₂ + 2H₂O

there is 4 total O on products side, which can make 2O₂

CH₄(g) + 2O₂(g) ---> 1CO₂(g) + 2H₂O(g)

6 0
3 years ago
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1. How does a star's life begin?
Phantasy [73]

Answer:

A star begins its life as a cloud of dust and gas (mainly hydrogen) known as a nebula. A protostar is formed when gravity causes the dust and gas of a nebula to clump together in a process called accretion. ... If a critical temperature in the core of a protostar is reached, then nuclear fusion begins and a star is born.

Explanation:

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4 0
3 years ago
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A 25.00 mL sample of of a sulfurous acid solution is completely neutralized using 17.12 mL of 0.13 M sodium hydroxide. What is t
Kryger [21]

Answer:

0.0445 M is the initial concentration of sulfurous acid.

Explanation:

H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_3

are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=25.00mL\\n_2=1\\M_2=0.13 M\\V_2=17.12 mL

Putting values in above equation, we get:

2\times M_1\times 25.00 mL=1\times 0.13 M\times 17.12 mL

x=\frac{1\times 0.13 M\times 17.12 mL}{2\times 25.00}=0.0445 M

0.0445 M is the initial concentration of sulfurous acid.

8 0
3 years ago
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