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2 years ago

Brandon answered 48 out of 60 questions correctly on his test. What was Brandon's score as a percent?

Mathematics

2 answers:

PilotLPTM [1.2K]2 years ago

5 0

Answer:

The answer to this question will be 80%

Mkey [24]2 years ago

3 0

Answer:

80%

Step-by-step explanation:

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This morning, the temperature was 80 ⁰F. It dropped 5 degrees per hour. In how many (h) hours did the temperature drop to at mos

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Answer: B or D

Step-by-step explanation:

5 times 8 (hours) is 40. Your input was correct, but you can try adding D too

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2 years ago

M-2<-8 or m/8>1 I don't know how to solve this

Shkiper50 [21]

I hope this helps you

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2 years ago

An architect plans to make a drawing of the room of a house. The segment LM represents the ceiling of the room. He wants to cons

aev [14]

Here are the steps

1: Put the compass on Q and make the width equal to the distance from Q to L. Extend line LM towards the left side of L and draw an arc hitting the line segment on the left side of L

2. Without changing the width and position of the compass, draw an arc between L and M.

3. Without changing the width of the compass, put the compass on the point of intersection of the arc and line LM (left side of L). Draw an arc above line LM.

4. Without changing the width of the compass, put the compass on the point of intersection of the arc and line LM (right side of L). Draw an arc above line LM.

5. Use a straight edge to make a line from the intersection of the two arcs above line LM to Q intersecting through L along the way.

8 0

2 years ago

Read 2 more answers

One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

See attachment for possibility tree

Solving (b): The total number of outcome

For urn 1

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

For urn 2

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

5 0

2 years ago

2/3 + 3/4 + 4/2. If a fraction appears in your answer, it should be in simplified form.

V125BC [204]

We must first make each fraction have a common denominator, this will be 12
2/3 * 4/4 = 8/12
3/4 * 3/3 = 9/12
4/2 * 6/6 = 24/12
we can then add the numerators of each fraction
8 + 9 + 24 = 41
so our answer is 41/12
we can not simplify any further and thus get
41/12

5 0

2 years ago