.3 = 3/10
.5 = 1/2
.05 = 1/20
.25 = 1/4
Answer:
D. 3x+(-2)=2x+4
Step-by-step explanation:
There is 2 red cubes of -1 so it has to be in parentheses, not combined like letter C.
The required equation of a line is y = 9/5 (4x - 12)
Given-
The point from which the line passes through is (3,2)
The slope of the given line m is -4/5.
Equation of the line
The linear equation of a line can be represented by a set of points on a graph using the equation of the line.
The standard form of the line passing through the point x₁, y₁
The slope m is given by,
m = (y - y₁) / (x - x₁)
Put the values of points and slope in the above equation, we get,
-4/5 = (y - 2) / (x - 3)
-4/5(x - 3) = y -2
-4x/5 + 12/5 = y - 2
-1/5 (4x - 12) + 2 = y
y = 9/5 (4x - 12)
The linear equation of a line can be represented by a set of points on a graph using the equation of the line. The following equation depicts a line that crosses (3, 2) and has a slope of -4/5: y = 9/5 (4x - 12)
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Answer:
z= 0.278
Step-by-step explanation:
Given data
n1= 60 ; n2 = 100
mean 1= x1`= 10.4; mean 2= x2`= 9.7
standard deviation 1= s1= 2.7 pounds ; standard deviation 2= s2 = 1.9 lb
We formulate our null and alternate hypothesis as
H0 = x`1- x`2 = 0 and H1 = x`1- x`2 ≠ 0 ( two sided)
We set level of significance α= 0.05
the test statistic to be used under H0 is
z = x1`- x2`/ √ s₁²/n₁ + s₂²/n₂
the critical region is z > ± 1.96
Computations
z= 10.4- 9.7/ √(2.7)²/60+( 1.9)²/ 100
z= 10.4- 9.7/ √ 7.29/60 + 3.61/100
z= 0.7/√ 0.1215+ 0.0361
z=0.7 /√0.1576
z= 0.7 (0.396988)
z= 0.2778= 0.278
Since the calculated value of z does not fall in the critical region so we accept the null hypothesis H0 = x`1- x`2 = 0 at 5 % significance level. In other words we conclude that the difference between mean scores is insignificant or merely due to chance.