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2 years ago

Solve the following. Write the answer on your sheet

Mathematics

1 answer:

jekas [21]2 years ago

4 0

Answer:

1) 157/20
2) 227/12
3) 271/35
4) 203/15
5) 93/8
6) 527/60
7) 48/5
8) 77/10
9) 37/21
10) 67/12

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horsena [70]

Answer:

880

Step-by-step explanation:

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3 years ago

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Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he

alexgriva [62]

Answer:

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

$9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$

$e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0$

By comparing with y′+p(t)y=g(t), we get

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous.

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3 years ago

**!!PLEASE ANSWER!!**

sammy [17]

Answer:

Answer: 155.12km

Step-by-step explanation:

sin(64˚) x 78 = 70.11 (2DP)

70.12 (2DP) + 85 = 155.1059356 (155.12 - 2DP)

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3 years ago

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nekit [7.7K]

The answer will be (x-9) with a little two in the corner *2

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3 years ago

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Algebra help please I need a equation please

Rudik [331]

K = s + 4
k + s = 26
s + 4 = 26
Subtract 4 from both sides of the equation.
s = 22
Steve ran 22 miles.

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3 years ago