Question

Please help me I'm so bad at math and doing AFDA really doesn't help.. Its quadratic equations matching solution sets.

Answer 1

Answer:

$(a)\ x + 4 = \±\sqrt9$ ---- $x =\{-7,- 1\}$

$(b)\ x - 4 = \±\sqrt9$ ---- $x = \{1,7\}$

$(c)\ x + 3 = \±\sqrt{16}$ ----- $x = \{-7,1\}$

$(d)\ x - 3 = \±\sqrt{16}$ ---- $x = \{-1,7\}$

Step-by-step explanation:

Given

The attached equations

Required

Match each with the solution

$(a)\ x + 4 = \±\sqrt9$

Take the square root of 9

$x + 4 = \±3$

Solve for x

$x =- 4 \±3$

Split

$x =\{- 4 -3,- 4 +3\}$

$x =\{-7,- 1\}$

$(b)\ x - 4 = \±\sqrt9$

Take the square root of 9

$x - 4 = \±3$

Solve for x

$x = 4 \±3$

Split

$x = \{4 -3,4+3\}$

$x = \{1,7\}$

$(c)\ x + 3 = \±\sqrt{16}$

Take the square root of 16

$x + 3 = \±4$

Solve for x

$x =- 3 \±4$

Split

$x = \{-3-4,-3+4\}$

$x = \{-7,1\}$

$(d)\ x - 3 = \±\sqrt{16}$

Take the square root of 16

$x - 3 = \±4$

Solve for x

$x =3 \±4$

Split

$x = \{3-4,3+4\}$

$x = \{-1,7\}$