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3 years ago

Please help me I'm so bad at math and doing AFDA really doesn't help.. Its quadratic equations matching solution sets.

Mathematics

1 answer:

stiv31 [10]3 years ago

6 0

Answer:

$(a)\ x + 4 = \±\sqrt9$ ---- $x =\{-7,- 1\}$

$(b)\ x - 4 = \±\sqrt9$ ---- $x = \{1,7\}$

$(c)\ x + 3 = \±\sqrt{16}$ ----- $x = \{-7,1\}$

$(d)\ x - 3 = \±\sqrt{16}$ ---- $x = \{-1,7\}$

Step-by-step explanation:

Given

The attached equations

Required

Match each with the solution

$(a)\ x + 4 = \±\sqrt9$

Take the square root of 9

$x + 4 = \±3$

Solve for x

$x =- 4 \±3$

Split

$x =\{- 4 -3,- 4 +3\}$

$x =\{-7,- 1\}$

$(b)\ x - 4 = \±\sqrt9$

Take the square root of 9

$x - 4 = \±3$

Solve for x

$x = 4 \±3$

Split

$x = \{4 -3,4+3\}$

$x = \{1,7\}$

$(c)\ x + 3 = \±\sqrt{16}$

Take the square root of 16

$x + 3 = \±4$

Solve for x

$x =- 3 \±4$

Split

$x = \{-3-4,-3+4\}$

$x = \{-7,1\}$

$(d)\ x - 3 = \±\sqrt{16}$

Take the square root of 16

$x - 3 = \±4$

Solve for x

$x =3 \±4$

Split

$x = \{3-4,3+4\}$

$x = \{-1,7\}$

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Express 5.03 as a fraction.

algol [13]

503 / 100

Convert the mixed number 5 3 100 into an improper fraction first by multiplying the denominator ( 100 ) by the whole number part ( 5 ) and add the numerator ( 3 ) to get the new numerator. Place the new numerator ( 503 ) over the old denominator ( 100 ) . 503 /100 .

Thanks,

Deku ❤

6 0

3 years ago

Read 2 more answers

PLS HELP ME W/ #8 ASAP

tiny-mole [99]

Answer:

x=2

TU:4(2)-1=7

UB: 3

TB: 10

Step-by-step explanation:

4x-1+2x-1=5x

6x-2=5x

6x=5x+2

subtract 5x from both sides

x=2

TU: (4x-1)

4(2)-1

8-1

TU:4(2)-1=7

UB: (2x-1)

2(2)-1

4-1

UB: 3

TB: 5(2)

TB: 10

7 0

3 years ago

Preview Activity 3.5.1. A spherical balloon is being inflated at a constant rate of 20 cubic inches per second. How fast is the

ArbitrLikvidat [17]

Answer:

The radius is increasing at a rate of approximately 0.044 in/s when the diameter is 12 inches.

Because $\frac{dr}{dt}=\frac{5}{36\pi }>\frac{dr}{dt}=\frac{5}{64\pi }$ the radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Let $r$ be the radius, $d$ the diameter, and $V$ the volume of the spherical balloon.

We know $\frac{dV}{dt}=20 \:{in^3/s}$ and we want to find $\frac{dr}{dt}$

The volume of a spherical balloon is given by

$V=\frac{4}{3} \pi r^3$

Taking the derivative with respect of time of both sides gives

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

We now substitute the values we know and we solve for $\frac{dr}{dt}$ :

$d=2r\\\\r=\frac{d}{2}$

$r=\frac{12}{2}=6$

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}\\\\\frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2} \\\\\frac{dr}{dt}=\frac{20}{4\pi(6)^2 } =\frac{5}{36\pi }\approx 0.044$

The radius is increasing at a rate of approximately 0.044 in/s when the diameter is 12 inches.

When d = 16, r = 8 and $\frac{dr}{dt}$ is:

$\frac{dr}{dt}=\frac{20}{4\pi(8)^2}=\frac{5}{64\pi }\approx 0.025$

The radius is increasing at a rate of approximately 0.025 in/s when the diameter is 16 inches.

Because $\frac{dr}{dt}=\frac{5}{36\pi }>\frac{dr}{dt}=\frac{5}{64\pi }$ the radius is changing more rapidly when the diameter is 12 inches.

8 0

3 years ago

In a sample of 400 voters, 360 indicated they favor the incumbent governor. The 95% confidence interval of voters not favoring t

Andru [333]

Answer:

0.071 to 0.129

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

In a sample of 400 voters, 360 indicated they favor the incumbent governor. This means that 400-360 = 40 do not favor the incumbent governor. So $n = 400, \pi = \frac{40}{400} = 0.1$