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Anestetic [448]
3 years ago
14

2.

Mathematics
1 answer:
zavuch27 [327]3 years ago
8 0
A. For y= 2x-1, the slope is 2 and the y intercept is -1. Therefore, we should first plot (0,-1). From there, for each increment of x, increase y by 2. For y= 4x-5, the slope is 4 and the y ntercelt is -5. Therefore we should plot (0,-5) and plot an increase of 4 on the y axis per increase of 1 on the x axis. The solution is where the lines cross.

B. (2,3)
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3 years ago
Calculus AB
wariber [46]
Assuming you mean
\lim_{x \to 4} \frac{\sqrt{x+5}-3}{4-x}

that means as x approaches 4

if we sub 0 for x we get
0/0
and intermitent form
use l'hopital's rule

so
take the derivitive of the top and bottom seperatly
l'hopitals rule is something like
if \lim_{x \to n} \frac{f(x)}{g(x)} results in 0/0 or -∞/∞ or∞/∞ then keep doing it until f(n)/g(n) gives a form that isn't intermitent

so

take derivitive of top and bottom
\dfrac{\frac{1}{2\sqrt{x+5}}}{-1}
now, if we subsitute 4 for x we get
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\dfrac{\frac{1}{2\sqrt{9}}}{-1}=

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8 0
3 years ago
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