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Darina [25.2K]
3 years ago
14

This is due in ten mins help plz

Mathematics
2 answers:
MAVERICK [17]3 years ago
5 0
3? I think is the answer for this
Musya8 [376]3 years ago
5 0
I’m pretty sure it’s three as well
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Aanand earns Rs 80 in 7 hours and pramode earns Rs 90 in 12 hours. find their ratio​
My name is Ann [436]

Answer:

1.671:1

Step-by-step explanation:

80/7=11.99(9) or ~12

90/12= 7.177(7)

11.99(9)/7.177(7)=1.671

1.671:1

6 0
3 years ago
A rectangular prism had a volume of 252 cubic centimeters. The length of the prism is 14 centimeters and the width of the prism
mojhsa [17]
<h2>Answer:</h2>

A prism is a solid object having two identical bases, hence the same cross section along the length. Prism are called after the name of their base. A rectangular prism is a solid whose base is a rectangle. Multiplying the three dimensions of a rectangular prism: length, width and height, gives us the volume of a prism:

V=L\times W\times H

FOR THE ORIGINAL PRISM WE HAVE THE FOLLOWING DIMENSIONS:

L=14cm \\ \\ W=6cm \\ \\ H=3cm

In fact, the volume is 252cm^3 because:

V=14\times 6\times 3 \therefore V=252cm^3

Now the height of the prism was changed from 3 centimeters to 6 centimeters to create a new rectangular prism, therefore:

FOR THE NEW PRISM WE HAVE THE FOLLOWING DIMENSIONS:

L=14cm \\ \\ W=6cm \\ \\ H=6cm

So the new volume is:

V=14\times 6\times 6 \therefore V=504cm^3

<h3><em>What do we know about the volume of the new prism?</em></h3>

<em>Well, the volume has increased from </em>252cm^3 \ to \ 504cm^3 <em>and since</em> 504=2\times 252 <em>we can say that the new volume is two times the original volume.</em>

8 0
2 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
Lapatulllka [165]

Answer:

Step-by-step explanation:

Given that there is a function of x,

f(x) = 2sin x + 2cos x,0\leq x\leq 2\pi

Let us find first and second derivative for f(x)

f'(x) = 2cosx -2sinx\\f"(x) = -2sinx-2cosx

When f'(x) =0 we have tanx = 1 and hence

a) f'(x) >0 for I and III quadrant

Hence increasing in (0, \pi/2) U(\pi,3\pi/2)\\

and decreasing in (\pi/2, \pi)U(3\pi/2,2\pi)

x=\frac{\pi}{4}, \frac{3\pi}{4}

f"(\pi/4)

Hence f has a maxima at x = pi/4 and minima at x = 3pi/4

b) Maximum value = 2sin \pi/4+2cos \pi/4 =2\sqrt{2}

Minimum value = 2sin 3\pi/4+2cos 3\pi/4 =-2\sqrt{2}

c)

f"(x) =0 gives tanx =-1

x= 3\pi/4, 7\pi/4

are points of inflection.

concave up in (3pi/4,7pi/4)

and concave down in (0,3pi/4)U(7pi/4,2pi)

3 0
3 years ago
HELP Urgent! Pls Help
algol [13]

Answer:

u have to put i on the other side of the angle abc

Step-by-step explanation:

first u gotta fince the grades of each angles

3 0
3 years ago
Which is a possible turning point for the continuous function f(x)? a (4, 0) b (2, –1) c (–2, 0) d (0, –2)
Arte-miy333 [17]

Answer:

B

Step-by-step explanation: I DID THIS TEST

4 0
3 years ago
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