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Vikki [24]
3 years ago
9

Find the first term of the sequence 4, 12, 36, 108.... which exceeds 20,000.

Mathematics
1 answer:
Schach [20]3 years ago
5 0

Answer:

43740

Step-by-step explanation:

its an exponential factor of 3 just multiply each answer by 3 to get the next one up

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What term best describes the point where the three medians of a triangle intersects
kirill115 [55]
CENTROID is the term used to describe the point where the three medians of a triangle intersect.

Centroid is the center of gravity of the triangle. It is one of the triangle's point of concurrency. Aside from "center of gravity", it is also known as "center of mass" and "barycenter".

Centroids are always inside the triangle. Since, the centroid is where three medians intersect, each median divides the triangle into two smaller triangles of equal area. The centroid is exactly two-thirds the way along each median.

Other types of triangle centers aside from Centroids are:
1) incenter
2) circumcenter
3) orthocenter


6 0
3 years ago
1. A number is drawn from the set {1,2,3,4,...,20} Find the probability that
Aleks [24]

Answer:

1.A. The number chosen is odd number

2.D. Drawing a number card

3.F. The ball is not white

Step-by-step explanation:

SANA NAKATULONG PO ITO

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6 0
3 years ago
Read 2 more answers
When finding the equation of a linear function in a table how do I find y when x is 0?
sesenic [268]
U need to find the equation of the line....and once u do that, sub in 0 for x and solve for y
3 0
3 years ago
Can someone plz help me
solong [7]

Answer:

16.3 N

Step-by-step explanation:

subtract if the forces are opposite

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

7 0
3 years ago
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