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xxTIMURxx [149]
3 years ago
9

Maria invests $600 in a bank account that earns simple interest. She earns $30 at the end of 12 months. Janae invests $350 at th

e same rate of interest for 12 months. How much money will Janae earn on her $350 investment after 12 months
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
6 0
I believe the answer is $17.50, she earned $30 off of $600 meaning she had a 5% interest rate and 5% of 350 is $17.50
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5x - 7 is a/an expression, inequality or equation?
Paul [167]
I can help you if you want
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3 years ago
The endpoints of EF are E(2, 3) and F(8, 11). The midpoint of EF is M.<br> Find the length of EM.
Serga [27]

The midpoint of EF is M. The length of EM is 5

Given :

The endpoints of EF are E(2, 3) and F(8, 11).

M is the midpoint of EF

Lets find out the midpoint M using midpoint formula

(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\E (x_1,y_1) is (2,3)\\F(x_2,y_2) is (8,11)

Substitute the values inside the formula

(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\\\(\frac{2+8}{2} ,\frac{3+11}{2} )\\\\(5,7)

Midpoint M is (4,7)

Now to find out length of EM, we use distance formula

Distance = \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\mathrm{The\:distance\:between\:}\left(2,\:3\right)\mathrm{\:and\:}\left(5,\:7\right)\\\sqrt{\left(5-2\right)^2+\left(7-3\right)^2}\\\sqrt{3^2+4^2} \\\sqrt{25}\\5

So, length of EM= 5

Learn more :  brainly.com/question/18332427

5 0
3 years ago
Work out an estimate for 456.2-51<br> _______<br><br> 0.0512
AnnZ [28]
It equals 7958.1. hope it helps
7 0
4 years ago
If 12+18=30 and A is the sum of the previous Then what is A+19?
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

if 12 + 18 = 30 and A is the sum of the previous...." the sum " is the result of addition.....means A = 30

so A + 19 = 30 + 19 = 49 <===

3 0
3 years ago
Which equation is the inverse of y = 100 – x2?
aleksandr82 [10.1K]
The function f be described by y=100- x^{2}

The graph of this function, is the graph of the parent function x^{2}, which is the parabola with vertex at (0, 0) which opes upwards:

i) reflected with respect to the y-axis, because of the minus

ii) shifted 100 units up

check the picture attached. 


A function has an inverse only if it is decreasing or increasing.


So we must divide the following cases for which the inverses exist:

i) y=100- x^{2} with domain (-infinity, 0]

ii) y=100- x^{2} with domain [0, infinity)


To find the formula for the inverse function g of f, we use the property:

f(g(x))=x

thus, 

f(g(x))=x\\\\ 100-[g(x)]^2=x\\\\g^2(x)=100-x\\\\g(x)= \mp\sqrt{100-x}



so each of - and + cases, are the inverses of 


i) y=100- x^{2} with domain (-infinity, 0]

ii) y=100- x^{2} with domain [0, infinity)


At this point, recall that the domain of a function, is the range of it's inverse function, 

and the range of the function, is the domain of the inverse function.

thus, 

the range of \sqrt{100-x}, which is [0,infinity) is the domain of 

i) y=100- x^{2} with domain [0,infinity)



So our answer is:

inverse of i) y=100- x^{2} with domain (-infinity, 0] is -\sqrt{100-x}


and the inverse of ii) y=100- x^{2} with domain [0, infinity) is 

\sqrt{100-x}

4 0
3 years ago
Read 2 more answers
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