Answer:
<h2>
<em>3</em><em>9</em><em> </em><em>units</em></h2>
<em>Solution,</em>
<em>Total </em><em>area=</em><em>Area </em><em>of </em><em>ABCD+</em><em> </em><em>Area </em><em>of </em><em>triangle </em><em>ADE</em>
<em>
</em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
1600*0.85
The answer is 1360 tickets..
If you look on jiskha you will find the answer you will be looking for just type it in B
For this case we have the following data:
So that the figure can be a rectangle, its diagonals must be equal, that is, 
In this way we have:
Clearing x we have:
Thus, x must be equal to 10 so that the figure is a rectangle.
Answer:
Option A
Answer:
12x - 6 ≤ - 18
Step-by-step explanation:
We will call "a number" x so
Twelve times a number would be:
12x
Then minus 6
12x - 6
Now we add the less than or equal to sign.
12x - 6 ≤
This is equal to negative eighteen, so:
12x - 6 ≤ - 18
As a bonus we can also solve for x.
12x - 6 = - 18 Add 6 to each side.
12x - 6 + 6 = -18 + 6
12x = -18 + 6
12x = -12 Divide each side by 12
12x/12 = -12/12
x = -12/12
x = -1
So we can say when x ≤ -1 Then 12x - 6 ≤ -18
