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3 years ago

9

(w2x−3)÷10⋅z when w=−9, x = 2.7, and z=−2/5

2 answers:

Margarita [4]3 years ago

6 0

Step-by-step explanation:

(-9)^2(2.7)-3/10(-2/5

= 81(2.7)-3/-2(2)

= 218.7-3/-4

= 215.7/-4

= -44

Katyanochek1 [597]3 years ago

3 0

w=-9
x=2.7
z=-2/5

$\\ \sf\longmapsto \dfrac{w^2x-3}{10z}$

$\\ \sf\longmapsto \dfrac{(-9)^2(2.7)-3}{10(-2/5)}$

$\\ \sf\longmapsto \dfrac{81(2.7)-3}{-2(2)}$

$\\ \sf\longmapsto \dfrac{218.7-3}{-4}$

$\\ \sf\longmapsto \dfrac{215.7}{-4}$

Rounding up numerator

$\\ \sf\longmapsto \dfrac{216}{-4}$

$\\ \sf\longmapsto -44$

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