Question

(w2x−3)÷10⋅z when w=−9, x = 2.7, and z=−2/5

Answer 1

Step-by-step explanation:

(-9)^2(2.7)-3/10(-2/5

= 81(2.7)-3/-2(2)

= 218.7-3/-4

= 215.7/-4

= -44

Answer 2

• w=-9
• x=2.7
• z=-2/5

$\\ \sf\longmapsto \dfrac{w^2x-3}{10z}$

$\\ \sf\longmapsto \dfrac{(-9)^2(2.7)-3}{10(-2/5)}$

$\\ \sf\longmapsto \dfrac{81(2.7)-3}{-2(2)}$

$\\ \sf\longmapsto \dfrac{218.7-3}{-4}$

$\\ \sf\longmapsto \dfrac{215.7}{-4}$

• Rounding up numerator

$\\ \sf\longmapsto \dfrac{216}{-4}$

$\\ \sf\longmapsto -44$