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densk [106]
3 years ago
9

(w2x−3)÷10⋅z when w=−9, x = 2.7, and z=−2/5

Mathematics
2 answers:
Margarita [4]3 years ago
6 0

Step-by-step explanation:

(-9)^2(2.7)-3/10(-2/5

= 81(2.7)-3/-2(2)

= 218.7-3/-4

= 215.7/-4

= -44

Katyanochek1 [597]3 years ago
3 0
  • w=-9
  • x=2.7
  • z=-2/5

\\ \sf\longmapsto \dfrac{w^2x-3}{10z}

\\ \sf\longmapsto \dfrac{(-9)^2(2.7)-3}{10(-2/5)}

\\ \sf\longmapsto \dfrac{81(2.7)-3}{-2(2)}

\\ \sf\longmapsto \dfrac{218.7-3}{-4}

\\ \sf\longmapsto \dfrac{215.7}{-4}

  • Rounding up numerator

\\ \sf\longmapsto \dfrac{216}{-4}

\\ \sf\longmapsto -44

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