Answer:
Step-by-step explanation:
Give me a sec to work it out
Step-by-step explanation:
given a normal distribution with the given parameters the probability (= the % of the area of the distribution curve) for a number to be between 203 and 1803 is
0.9987
so, 99.87% of all numbers are expected to be in that range.
for 350,000 numbers that means
350,000×0.9987 = 349,545 numbers are expected to be between 203 and 1803.
D & C are the correct answers.This is because of the Distributive Property.
y+y+y +3z = 3y + 3z.
3(y+z) also gives you 3y + 3z.
C is correct because everything adds up to 3y +3z:
2y+2z+y+z = 3y +3z
Answer:
V =41.41³
A = 94.41²
----
V =225.16³
SA =283.25²
----
V = 64³
SA =113.32²
----
V =433.33³
SA = 378.57²
Step-by-step explanation:
Picture 2 = a = 1/2 base = 3.5 x 3.5 = 12.25 b= 5 x 5 = 25
c²= a² + b² = 3.5² + 5²
c ²= √12.25 + √25
c ²= √ 37.5 = 6.12372435696
c ² = 6.1237 missing side
Picture 1 + 2 formula SA = bh + (s1 + s2 + s3)H
V = V= 1/2 b x h h x SA
Picture 3 + 4 formula SA= a²+ 2a a² / 4 + h² V= a² h/3