First, fint the roots of the equation 
1.
2. You can see that this equation has two different real roots. Note that you can make this statement without finding roots, only knowing the value of discriminant: since D=81>0, then the equation has two different real roots.
The answer to this question would be: p+q+r = 2 + 17 + 39= 58
In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number.
There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73
The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39
p+q+r = 2 + 17 + 39= 58
Answer:
Using sum and product method you can simplify the top as:
x^2-4x-5 = (x-5)(x+1) and x^2-5x+4 = (x-4)(x-1)
The x-4 and the x+1 cancel each other out and you will be left with
(x-5)/(x-1)
Step-by-step explanation:
