Answer: They will be the same after 3 weeks $127
Step-by-step explanation:
Since ABC is a 90-60-30 triangle, it is half of an equilateral triangle. This means that BC is half AC, i.e. 17.
So, we have
![AB = \sqrt{AC^2-BC^2}=\sqrt{AC^2-\left(\dfrac{AC}{2}\right)^2}=\dfrac{\sqrt{3}}{2}AC = \sqrt{3}\cdot BC =\sqrt{3}\cdot 17\approx 29.4](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7BAC%5E2-BC%5E2%7D%3D%5Csqrt%7BAC%5E2-%5Cleft%28%5Cdfrac%7BAC%7D%7B2%7D%5Cright%29%5E2%7D%3D%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B2%7DAC%20%3D%20%5Csqrt%7B3%7D%5Ccdot%20BC%20%3D%5Csqrt%7B3%7D%5Ccdot%2017%5Capprox%2029.4)
So, the perimeter is
![AD+DC+BC+AB\approx34+34+17+29.4\approx 114.4](https://tex.z-dn.net/?f=AD%2BDC%2BBC%2BAB%5Capprox34%2B34%2B17%2B29.4%5Capprox%20114.4)
Answer:
615.44 m²
Step-by-step explanation:
the area of circle = 3.14 x 14² = 3.14×196
= 615.44 m²
Answer:
138.16 square feet
Step-by-step explanation:
The surface area of the cylinder consists of one rectangle and two circles.
1. The radius of the circle is 4 ft, then the area of the circle is
![A_{circle}=\pi r^2 =\pi \cdot 4^2 =16\pi \ ft^2](https://tex.z-dn.net/?f=A_%7Bcircle%7D%3D%5Cpi%20r%5E2%20%3D%5Cpi%20%5Ccdot%204%5E2%20%3D16%5Cpi%20%5C%20ft%5E2)
2. The width of the rectangle is 1.5 ft, the length of the rectangle is the circumference of the circle.
Find the circumference:
![C=2\pi r=2\pi \cdot 4=8\pi \ ft](https://tex.z-dn.net/?f=C%3D2%5Cpi%20r%3D2%5Cpi%20%5Ccdot%204%3D8%5Cpi%20%5C%20ft)
Hence,
![A_{rectangle}=1.5\cdot 8\pi =12\pi \ ft^2](https://tex.z-dn.net/?f=A_%7Brectangle%7D%3D1.5%5Ccdot%208%5Cpi%20%3D12%5Cpi%20%5C%20ft%5E2)
3. The surface area of the cylinder is
![SA=2A_{circle}+A_{rectangle}=\\ \\=2\cdot 16\pi +12\pi =32\pi +12\pi =44\pi \approx \\ \\\approx 44\cdot 3.14=138.16\ ft^2](https://tex.z-dn.net/?f=SA%3D2A_%7Bcircle%7D%2BA_%7Brectangle%7D%3D%5C%5C%20%5C%5C%3D2%5Ccdot%2016%5Cpi%20%2B12%5Cpi%20%3D32%5Cpi%20%2B12%5Cpi%20%3D44%5Cpi%20%5Capprox%20%5C%5C%20%5C%5C%5Capprox%2044%5Ccdot%203.14%3D138.16%5C%20ft%5E2)