1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aivan3 [116]
3 years ago
13

Choose the answer that shows 5^-15 rewrite using a positive exponent? ​

Mathematics
2 answers:
Mashcka [7]3 years ago
7 0

Answer:

1/5^15

Step-by-step explanation:

You use the exponent rule:

a^-b = 1/a^b

Lemur [1.5K]3 years ago
6 0

Answer:

the \: ans =   \boxed{\frac{1}{5 {}^{15} } }

Step-by-step explanation:

since \: anything \: raised \: to \: power \:  (- whatever) \: is \: same \: as \to \frac{1}{anything \: raised \: to \: power \: whatever}  \\ so \to \: x {}^{ - 8}  =  \frac{1}{ {x}^{8} }  \\  \\ hence \to \boxed{  {5}^{ - 15}  =  \frac{1}{5 {}^{15} } }

♨Rage♨

You might be interested in
You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
Vikki [24]

The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

  • R = Original amount of Cesium
  • R' = New amount of cesium
  • T = Total time
  • t = Half-life

From the question,

Given:

  • R = 8640
  • T = 120 years
  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
  • R' = 8640/2^{4}
  • R' = 8640/16
  • R' = 540 grams.

Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

4 0
1 year ago
Please show all steps thank you
madreJ [45]
I know I'm definitely wrong: 540. it looks like a right angle. 
I did on the calculator:
18 * 90 = 1620
1620 / 3 = 540
6 0
2 years ago
Read 2 more answers
Louisa used Downtown Taxi, which charges $2 for the first mile and $1.10 for each additional mile. Pietro used Uptown Cab, which
soldier1979 [14.2K]

Answer: 21 miles

Step-by-step explanation:

6 0
2 years ago
A pair of jeans is on sale for 20% off. The sale price is $55.00. What is the original amount of the pair of jeans?
konstantin123 [22]

Answer: 275$

I'm not entirely sure I did this right! But at least try!!!

Step-by-step explanation:

20/100 = 55/x (cross multiply)

20x = 5,500 (divide)

X = 275

5 0
2 years ago
Method of Least Squares, Evaluation of Cost Equation Lassiter Company used the method of least squares to develop a cost equatio
maksim [4K]

Solution :

1). The cost of the formula is given as :

   $ 19,350 + $12 x

2). 95% \text{confidence interval} for the prediction is :

    $21430 - 1.96 \times 220 < \text{Yf} < 21430+1.96 \times 220$

     $20998.8 < \text{Yf} < 21861.2$

     $20999 < \text{Yf} < 21861$    (rounding off)

3). r = 0.92

Therefore, $r^2 = 0.8464$

That is 84.64 % of the variability in the moving cost is best explained by the number of moves.

3 0
3 years ago
Other questions:
  • What property is illustrated in the equation 15•1=15
    15·2 answers
  • How many decigrams equal 1 dekagram
    9·2 answers
  • Please Help.... 50 points.
    5·2 answers
  • Please please help me im really struggling
    5·1 answer
  • WILL MARK BRAINLIEST! THANK YOUUUU
    10·2 answers
  • Two math teachers come together and write math problems about fruit vendors. If Teacher A can write 50 problems in 60 minutes an
    10·2 answers
  • Solve the quadratic equation by using either a numeric or a graphic approach.
    5·1 answer
  • Question Help
    7·2 answers
  • 4a) The vertices of a triangle are P(-7, -4) Q(-7, -8) and R(3, -3). What are the
    13·1 answer
  • Make l the subject of formula when a=lb
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!