Answer: A=100(12)t5.27
Step-by-step explanation:
Assume / and ^ got lost from eqns.
A(t) = initial × (1/2)^(t/halflife)
So initial = 100, halflife = 5.27,
A=100(12)t5.27 means A=100(1/2)^(t/5.27)
so that A is 50 when t is 5.27
Answer:
? = 56.
Step-by-step explanation:
In the problem, the side 20 corresponds to side 32 and side 20 + 35 corresponds to side 32 + ?.
? + 32 = 8 * 11
? + 32 = 88
? = 56.
Hope this helps!
Do you have a pic so I can answer your question
Answer:
Lower Bound = 2.996
Upper bound = 3.244
Step-by-step explanation:
Answer:
New avaerage if 2 students (15 year old) left = 13
Step-by-step explanation:
Given:
Average age of 20 students = 13.2
Find:
New avaerage if 2 students (15 year old) left
Computtaion:
Sum of all 20 student's age = 20 x 13.2
Sum of all 20 student's age = 264
Sum of current 18 student's age = 264 - 15 - 15
Sum of current 18 student's age = 234
New avaerage if 2 students (15 year old) left = 234 / 18
New avaerage if 2 students (15 year old) left = 13
