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Kazeer [188]
3 years ago
14

You received partial credit in th

Mathematics
1 answer:
Blababa [14]3 years ago
5 0

Answer:

Expected value would be $ 0.896

Step-by-step explanation:

Given,

The price of the lottery ticket = $44800000,

Also, the probability of winning the grand prize = .000000020,

Thus, the expected value of the lottery ticket = value of the lottery ticket × probability of getting the lottery ticket

= 44800000 × .000000020

= $0.896

Note : value of lottery ticket = prize amount - cost of each ticket,

Here the cost price of a ticket is not given,

That's why we did not consider it.

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Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
aliya0001 [1]

Answer:

A=1500-1450e^{-\dfrac{t}{250}}

Step-by-step explanation:

The large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved.

Volume = 500 gallons

Initial Amount of Salt, A(0)=50 pounds

Brine solution with concentration of 2 lb/gal is pumped into the tank at a rate of 3 gal/min

R_{in} =(concentration of salt in inflow)(input rate of brine)

=(2\frac{lbs}{gal})( 3\frac{gal}{min})\\R_{in}=6\frac{lbs}{min}

When the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

Concentration c(t) of the salt in the tank at time t

Concentration, C(t)=\dfrac{Amount}{Volume}=\dfrac{A(t)}{500}

R_{out}=(concentration of salt in outflow)(output rate of brine)

=(\frac{A(t)}{500})( 2\frac{gal}{min})\\R_{out}=\dfrac{A}{250}

Now, the rate of change of the amount of salt in the tank

\dfrac{dA}{dt}=R_{in}-R_{out}

\dfrac{dA}{dt}=6-\dfrac{A}{250}

We solve the resulting differential equation by separation of variables.  

\dfrac{dA}{dt}+\dfrac{A}{250}=6\\$The integrating factor: e^{\int \frac{1}{250}dt} =e^{\frac{t}{250}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{250}}+\dfrac{A}{250}e^{\frac{t}{250}}=6e^{\frac{t}{250}}\\(Ae^{\frac{t}{250}})'=6e^{\frac{t}{250}}

Taking the integral of both sides

\int(Ae^{\frac{t}{250}})'=\int 6e^{\frac{t}{250}} dt\\Ae^{\frac{t}{250}}=6*250e^{\frac{t}{250}}+C, $(C a constant of integration)\\Ae^{\frac{t}{250}}=1500e^{\frac{t}{250}}+C\\$Divide all through by e^{\frac{t}{250}}\\A(t)=1500+Ce^{-\frac{t}{250}}

Recall that when t=0, A(t)=50 (our initial condition)

50=1500+Ce^{-\frac{0}{250}}50=1500+Ce^{0}\\C=-1450\\$Therefore the amount of salt in the tank at any time t is:\\A=1500-1450e^{-\dfrac{t}{250}}

4 0
4 years ago
How can you represent a rate with 100 as the whole?<br><br> Please need help
Levart [38]

Answer:

How to Calculate a Rate. "Rate" simply means the number of things per some other number, usually 100 or 1,000 or some other multiple of 10. A percentage is a rate per 100. Infant mortality rates are calculated per 1,000.

Step-by-step explanation:

7 0
4 years ago
Coach Johnson has 450 baseballs to give to 30 players. How many baseballs will each player get?
enyata [817]

Answer:

15. Hope it helps!

Step-by-step explanation:

7 0
3 years ago
A population mean of 360, a standard deviation of 4, and a margin of error of 2.5%
Ad libitum [116K]

Answer:

(351.04, 368.96)

Step-by-step explanation:

Given that population mean= 360

Std devitaion = 4

margin of error = 2.5%= 0.025

Since population std deviation is known we can use Z critical value

For two tailed critical value for 2.5% would be

2.24

Margin of error = ±Critical value*std deviation

= ±2.24(4)

= ±8.96

Confidence interval =(Mean - margin of error, mean + margin of error)

=(360-8.96, 360+8,.96)\\= (351.04, 368.96)

3 0
4 years ago
X=5 then 3x + 2 =<br><br><br> Pls help I don't know
erma4kov [3.2K]

Answer:

17

Step-by-step explanation:

Substitute "x" for "5" in the equation

3(5) + 2

15 + 2

17

5 0
3 years ago
Read 2 more answers
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