Answer:
see explanation
Step-by-step explanation:
Point A is the Incentre of the triangle
This is the point where the 3 angle bisectors intersect
The incentre is equally far away from the triangle's 3 sides , then
AM = AL = 6
Your answer should be -2
Use PEMDAS if confused!
Parentheses
Exponent
Multiplication
Division
Addition
Subtraction.
You would first calculate the number in between your parentheses which would give you -1. Then do -1 to the power of 4(-1^4) which still gives you -1 and then multiply it by 2 which should give you your answer -2. :)
Hope this helps.
Answer:
See attached diagram
Step-by-step explanation:
Graph the solution of the inequality
First, draw the dotted line
(dotted because the sign of the inequality is <). Then determine wich part of the coordinate plane should be shaded. Since the origin's coordinates satisfy the inequality, then this point should belong to the region (red part on the diagram).
Graph the solution of the inequality
First, draw the solid line
(solid because the sign of the inequality is ≥). Then determine wich part of the coordinate plane should be shaded. Since the origin's coordinates satisfy the inequality, then this point should belong to the region (blue part on the diagram).
The intersection of both regions is the solution of the system of two inequalities.
Let x represent the cost of book B
Book A: $17.50
Book B: x
Sales tax: (A + B) x 6% = .06(17.50 + x) = 1.05 + .06x
book A + book B + sales tax = total cost
(17.50) + (x) + (1.05 + .06x) = 44.52 <em>plugged in all of the values</em>
18.55 + 1.06x = 44.52 <em>added like terms</em>
1.06x = 25.97 <em>subtracted 18.55 from both sides</em>
x = 24.50 divided 1.06 from both sides
Answer: $24.50
Answer:
The probability that all are male of choosing '3' students
P(E) = 0.067 = 6.71%
Step-by-step explanation:
Let 'M' be the event of selecting males n(M) = 12
Number of ways of choosing 3 students From all males and females

Number of ways of choosing 3 students From all males

The probability that all are male of choosing '3' students


P(E) = 0.067 = 6.71%
<u><em>Final answer</em></u>:-
The probability that all are male of choosing '3' students
P(E) = 0.067 = 6.71%