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Veronika [31]
4 years ago
15

Could someone check my answer please

Mathematics
2 answers:
Butoxors [25]4 years ago
3 0
Hello there! The axis of symmetry is the vertical line where the parabola can be divided and there are two equal halves. The vertex is on that line. The point where this occurs is all in the positive range, so that eliminates B, C, and D. (0.5, 4.25) is the vertex and 0.5 is the axis of symmetry. The answer is A. Your answer is correct.
anygoal [31]4 years ago
3 0
The question is correct
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A company is trying out a new marketing technique that begin by asking One customer to tell three friends about a product in the
Nostrana [21]

Week 1 : 1 customer tells 3 friends

Week 2: 3 new customers tell 9 friends

Week 3: 9 new customers tell 27 friends

If w represents number of weeks, then (C) represents the model appropriately. Let's see how:

Putting w = 1 , 2 and 3 in each of the options

(A) 3w: 3 for week 1, 6 for week 2, 9 for week 3 ⇒ INCORRECT

(B) w^3: 1 for week 1, 8 for week 2, 27 for week 3 ⇒ INCORRECT

(C) 3^w: 3 for week 1, 9 for week 2, 27 for week 3 ⇒ CORRECT

(D) 3w^3: 3 for week 1, 24 for week 2, 81 for week 3 ⇒ INCORRECT

Hence, the answer is (C)


5 0
3 years ago
Read 2 more answers
Question Help The circumference of the hub cap of a tire is 73.54 centimeters. Find the area of this hub cap. Use 3.14 for it. U
Archy [21]
See attached picture

8 0
2 years ago
Please need help on this question 20 points
notsponge [240]

Answer:C

Step-by-step explanation:

3 0
3 years ago
2/3 + 3/4 + 4/2. If a fraction appears in your answer, it should be in simplified form.
V125BC [204]
We must first make each fraction have a common denominator, this will be 12
2/3 * 4/4 = 8/12
3/4 * 3/3 = 9/12
4/2 * 6/6 = 24/12
we can then add the numerators of each fraction
8 + 9 + 24 = 41
so our answer is 41/12
we can not simplify any further and thus get
41/12
5 0
3 years ago
1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x
qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is (2x+10)^\circ, so the measure of arc DF is

m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ

The inscribed angle theorem tells us that the central angle subtended by arc DF, \angle DOF, has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

m\angle DOF=2m\angle OEF=64^\circ

so the measure of arc DF is also 64 degrees. So we have

170-2x=64\implies106=2x\implies\boxed{x=53}

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}

7 0
3 years ago
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