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2 years ago

Please I need help I’m not good at math

Mathematics

1 answer:

PolarNik [594]2 years ago

6 0

Answer:

Step-by-step explanation:

because you do 2-1 and then 3 * 3 the equation would look like this

1 + (3*3) /

1+9/ 3

1 + 3

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What is 23lb is it greater than or less than or equal to365oz

GuDViN [60]

23 pounds is 368 ounces

8 0

3 years ago

If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c

dolphi86 [110]

Given:

$(ax+2)(bx+7)=15x^2+cx+14$

And

$a+b=8$

Required:

To find the two possible values of c.

Explanation:

Consider

$\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}$

$\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}$

And also given

$a+b=8---(2)$

Now from (1) and (2), we get

$\begin{gathered} a+\frac{15}{a}=8 \\ \\ a^2+15=8a \\ \\ a^2-8a+15=0 \end{gathered}$ $a=3,5$

Now put a in (1) we get

$\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}$

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

$\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}$

When a=5 and b=3, we have

$\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}$

Final Answer:

The option D is correct.

31 and 41

8 0

11 months ago

Estimate the product. Solve using an area model and the standard algorithm. Remember to express your products in standard form.

snow_tiger [21]

Answer:

Step-by-step explanation:

Using the area model and standard algorithm, we have:

332 (tenths)

× 21

332

664

6972 tenths = 697.2

30 + 3 tenths

1 300 32 332

20 600 64 664

33.2 × 21 = 30 × 1 = 30

8 0

2 years ago

You have 6 dollars +12 pennies +to quarters + 4 dimes=2 nickels how much do you have

alina1380 [7]

You may have $26 I not a genius but this is easy

3 0

3 years ago

In triangle ABC below, sinC=h/a and sinA=h/c. Which of the following combines the two sine ratios into one equation?

LenaWriter [7]

We know:

$sin(C)=\frac{h}{a}$

and

$sin(A)=\frac{h}{c}$

These expressions have an $h$ term in common. We can combine them if we can find forms of the expressions in terms of $h$ :

$h=a(sin(C))$

$h=c(sin(A))$

Now, because $h=h$ (by the reflexive property), we can write:

$a(sin(C))=c(sin(A))$

This is our answer, A.

4 0

3 years ago