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sergiy2304 [10]

2 years ago

5

Please I need help I’m not good at math

1 answer:

PolarNik [594]2 years ago

6 0

Answer:

4

Step-by-step explanation:

because you do 2-1 and then 3 * 3 the equation would look like this

1 + (3*3) /

1+9/ 3

1 + 3

4

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On a number line, the coordinates of X, Y, Z, and W are −7, −2, 2, and 7, respectively. Find the lengths of the two segme

liubo4ka [24]

FIRST WE ...
subtract one value to the other to see how many valued we have in between
-7 - (-2) = 5
7-2=5
Both of the lines XY AND ZW have 5 units or points in between them.
Length = 5 units
They are congruent since XY = ZW in length and essentially are the same line but at different points

3 0

3 years ago

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

so

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

3 years ago

Is the following conditional true?

kakasveta [241]

Answer:

Yes

Step-by-step explanation:

3 0

3 years ago

Word related with English<br>

lutik1710 [3]

Answer:

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Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A line that includes the points (6,h) and (7,−10) has a slope of −7.

Sonbull [250]

Answer:

h=-3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

-7=(-10-h)/(7-6)

-7=(-10-h)/1

-7*1=-10-h

-7=-10-h

h=-10-(-7)

h=-10+7

h=-3

7 0

3 years ago