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ddd [48]
3 years ago
7

Please help me!!!

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
8 0
Well, the general form for point-slope form is y-ysub1= m(x-xsub1). In the general form,  ysub1 stands for the y-coordinate and xsub1 stands for the x-coordinate, and m stands for the slope. When writing in point-slope form, we need the slop and one ordered pair. 

The equation has already given us two ordered pairs but it doesn't give us the slope. We just need to find the slope between these two points, which is 3/1, or just 3. Then we pick one of the ordered pair they gave us and plug in the general form. 

I'll go with the first ordered pair, (2,1). The y and the x in the equation, don't plug them in, leave them as it is, we only need to plug in the slope and the two coordinates. So we get y-1=3(x-2). 

I'll only do the first ordered pain for you, and you should be able to do the second one.
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If the measure of angle 4 is (11 x) degrees and angle 3 is (4 x) degrees, what is the measure of angle 3 in degrees?
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In one day, a book store earned $199 in sales for 4 copies of a new cookbook and 5 copies of a new science fiction novel. On the
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Answer:

The cookbook costs $36 per copy while the science fiction costs $11 per copy

Step-by-step explanation:

Here in this question, we are interested in calculating the price of the cookbook and the price of the science fiction novel.

Since we do not know the price of each, we start by assigning variables to stand in for these unknown prices.

Let the price of the cookbook be $x , while the price of the science fiction be $y

Now, on the first day, 4 copies of the cookbook and 5 copies of the fiction;

mathematically that would be 4 * x and 5 * y

We add both and sum to be $199

Thus we have;

4x + 5y = 199 ••••••••••(i)

On the second day;

3 copies of cookbook 3 * x = 3x with 4 copies of science fiction 4 * y

Adding both yielded 152;

Thus, we have ;

3x + 4y = 152••••••••••(ii)

So we need to solve both equations simultaneously to get the values of x and y

4x + 5y = 199

3x + 4y = 152

Multiply equation i by 3 and equation ii by 4

3 * 4x + 5y = 199

4 * 3x + 4y = 152

12x + 15y = 597

12x + 16y = 608

Now, subtract multiplied equation ii from multiplied equation i

(12x-12x) + (15y-16y) = (597-608)

-y = -11

y = 11

To get x, simply substitute in any of the equations;

let’s use equation 1

4x + 5y = 199

4x + 5(11) = 199

4x + 55 = 199

4x = 199-55

4x = 144

x = 144/4

x = 36

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