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CaHeK987 [17]
3 years ago
15

A man left one-third of his property to his son, one-fourth to his daughter and the remaining rupees 20000 to his wife. How much

money did the man leave?
#No spam​
Mathematics
2 answers:
fredd [130]3 years ago
6 0

Answer:

₹48,000

Step-by-step explanation:

Let the money with the man = ₹ x

Share given to his son = \frac{1}{3}x

Share given to his daughter = \frac{1}{4}x

Share given to his wife =  ₹ 20000

Total money  =  ₹ x

x-\dfrac{1}{3}x-\dfrac{1}{4}x=20000\\\\ \dfrac{1*12}{1*12}x-\dfrac{1*4}{3*4}x-\dfrac{1*3}{4*3}=20000\\\\\dfrac{12}{12}x-\dfrac{4}{12}x-\dfrac{3}{12}x=20000\\\\\dfrac{12-4-3}{12}x=20000\\\\\dfrac{5}{12}x=20000\\\\x=20000*\dfrac{12}{5}\\\\

x = 4000 * 12

x = ₹48,000

Tasya [4]3 years ago
4 0

Answer:

48000 rupees

Step-by-step explanation:

1/3+1/4=7/12. This means that the 20000 rupees are 5/12 of his whole fortune. Therefore, 20000÷5×12=48000 is the left money.

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