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Otrada [13]
3 years ago
9

Uh could someone help me on this please?

Mathematics
2 answers:
sukhopar [10]3 years ago
8 0

Answer:

39×99=3861.

85×43+43×15=4300

docker41 [41]3 years ago
8 0

39 multiple 99= 3861

Step-by-step explanation:

85 multiple 43 add 15=4300

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Please help me i really need help please
maw [93]

Answer:

39°

Step-by-step explanation:

IM assuming xyz is a triangle

180 - 113 - 28 = 67 - 28 = 39

3 0
2 years ago
The nth term of a sequence is 3n^2- 1
Thepotemich [5.8K]

Answer: The number that belongs to both sequences is 26.

Step-by-step explanation:

We have two sequences, let's call one as A and the other as B.

The n-th term of sequence A is written as:

aₙ = 3*n^2 - 1

the nth term of sequence B is written as:

bₙ = 30 - n^2

We want to find a term that belongs to both sequences, (it can be for different integers, we can use n for sequence A and x for sequence B)

Then we want to find:

aₙ = bₓ

where n and x are integer numbers.

Then we will heave:

3*n^2 - 1 = 30 - x^2

To find the pair, we could isolate one of the variables, then input different integers in the other variable and see if the outcome is also an integer.

Let's isolate n.

3*n^2 = 30 - x^2 + 1

3*n^2 = 31 - x^2

n^2 = (31 - x^2)/3

n = √(  (31 - x^2)/3)

Now let's input different values for x, and see if the outcome is also an integer, notice that x is in a negative term inside a square root, then we have only a few values of x such that the equation can be true.

Then let's start with x = 1.

n(1) = √(  (31 - 1^2)/3) = √(30/3) = √10

We know that √10 is not an integer.

now with x = 2,

n(2) = √(  (31 - 2^2)/3)  = √( (31 - 4)/3) = √(27/3) = √9 = 3

then if x = 2, we have n = 3.

Both of them are integers, then we get:

a₂ = 3*(3)^2 - 1 = 27 - 1 = 26

b₃ = 30 - 2^2 = 30 - 4 = 26

The number that belongs to both sequences is 26.

5 0
2 years ago
What is a quotient of 3/10÷8/5 out of these forms 1. 3/16 2. 4/9 3. 15/80 4. 24/50
Zanzabum

Answer:

option 1

Step-by-step explanation:

\frac{3}{10} ÷ \frac{8}{5}

• leave the first fraction

• change division to multiplication

•  turn the second fraction 'upside down'

= \frac{3}{10} × \frac{5}{8} ( cancel 5 and 10 by 5 )

= \frac{3}{2} × \frac{1}{8}

= \frac{3}{16}

8 0
2 years ago
Solve for p: 5(4x+p)=w
Olenka [21]
P = w/5 - 4x is the answer
6 0
2 years ago
Read 2 more answers
Which sequence of transformations creates a similar but not congruent triangle
Gwar [14]

A a dilation and reflection

dilation will make bigger or smaller therefore it cannot be congruent


5 0
3 years ago
Read 2 more answers
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