Answer:
Let p be the number of pens and let n be the number of notebooks.
4 notebooks + 3 pens cost $96 so 4n + 3p = 96
2 notebooks + 2 pens cost $54 so 2n + 2p = 54
We find n and p by solving the system of linear equations:
4n + 3p = 96
2n + 2p = 54
4n + 3p = 96
4n + 4p = 108 (we multiply this by 2 to cancel out 4n in both equations)
We then subtract the two equations:
(4n + 3p) - (4n + 4p) = 96 - 108
-p = -12
p = 12
So, a pen costs 12 dollars. We can use p to find n. We substitute 12 for p in one of our earlier equations:
2n + 2p = 54
2n + 2(12) = 54
2n + 24 = 54
2n = 30
n = 15
So, a notebook costs 15 dollars and a pen costs 12. Now, we need to find the cost of 8 notebooks and 7 pens:
8n + 7p = ?
8(15) + 7(12) = ?
120 + 84 = 204.
Thus, 8 notebooks and 7 pens cost 204 dollars (why is it so expensive lol).
Answer:
1/10
Step-by-step explanation:
93÷93 930÷93
=1/10
Answer:
Below.
Step-by-step explanation:
I've drawn the answers to (c) and (g) in the attached picture.
First mark the radar point and draw the N line vertically up from this point.
The bearing is the angle, drawn clockwise, from The North (N) line on the radar point. The lines drawn are 5 and 6.5 cms long to indicate the 5 and 6.5 miles.
I have estimated the angles. To draw them accurately you'll need a protractor.
I don’t know- the first thing I would think is that x=15*y because 30=15*2
So that’s my thinking, which means that if x=5, then y=5/15 or 1/3 or as a decimal .33
However I’m not sure if that’s right- I hope it helps!
