Find the equation of a line perpendicular to y = -3 passing through the coordinate (2, 6).
1 answer:
Answer:
for two lines to be perpendicular m2 = -1/m2
using the formula y= mx+c
m1 = 0
for the lines to be perpendicular to each other(m2 = -1/0 )
Note: -1/0 is undefined
using the formula y-y1 = m(x-x1)
y -6 = -1/0(x-2)
cross multiply
0 = -1(x-2)
0 = -x+2
x =2(equation of the line)
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