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2 years ago

Find the equation of a line perpendicular to y = -3 passing through the coordinate (2, 6).

Mathematics

1 answer:

Vlad [161]2 years ago

6 0

Answer:

for two lines to be perpendicular m2 = -1/m2

using the formula y= mx+c

m1 = 0

for the lines to be perpendicular to each other(m2 = -1/0 )

Note: -1/0 is undefined

using the formula y-y1 = m(x-x1)

y -6 = -1/0(x-2)

cross multiply

0 = -1(x-2)

0 = -x+2

x =2(equation of the line)

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Solve each equation

Darya [45]

Answer:

r= 0

r= 1

b= -3

x= -3

Step-by-step explanation:

4r-8r=0

-4r=0

r=0

-15=-8r-7r

-15= -15r

r=1

3b+7-1=-3

3b= -3-7+1

3b= -9

b= -9/3

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3x+1-6x=7

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7 0

3 years ago

What is the inverse of the given relation y = 7x² ?

beks73 [17]

Answer:

y = square root(x/7)

Step-by-step explanation:

switch x and y

x = 7y^2

solve for y

x/7 = y^2

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y= square root(x/7)

7 0

2 years ago

Part III: Bailey works part-time at a movie theater. The theater pays employees an hourly wage based on their length of employme

frutty [35]

Given the following table showing the hourly wages of employees of a movie theater based on their length of employment.

<span>Length of employment (months)         Hourly wage (dollars/hour)
6 months    7.55
12 months    7.85
18 months    8.15
24 months    8.45

To obtain an algebraic expression </span>that describes how much Bailey’s employer pays part-time workers, we take two points from the table.

Recall that the equation of a linear function satisfying two points
$(x_1,y_1)$ and $(x_2,y_2)$
is given by
$\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}$

Given the two points (6, 7.55) and (12, 7.85), the algebraic expression relating the two points is given by
$\frac{y-7.55}{x-6} = \frac{7.85-7.55}{12-6} = \frac{0.3}{6} \\ \\ 6(y-7.55)=0.3(x-6) \\ \\ 6y-45.3=0.3x-1.8 \\ \\ 0.3x-6y=-43.5$

Therefore, the <span>algebraic expression that describes how much Bailey’s employer pays part-time workers is
$0.3x-6y=-43.5$ </span>

5 0

3 years ago

Drag each number to the correct location on the table.

ASHA 777 [7]

Answer:

$\text{Rational number} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{ Irrational number}$

$3\sqrt{25} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \sqrt{141}\\\\\sqrt{256} \\\\1. \overline{ 1625} \\\\\frac{-11}{151}$

Step-by-step explanation:

Since we believe it

The number sequence is that those which can be described as $\frac{p}{q}$ and that is not ending and recurring. Figures that are unreasonable are also the ones, that are not $\frac{p}{q}$ and therefore are non-ending, non-recurring.