Well, a distance-preserving transformation is called a rigid motion, and the name suggests that it <em>moves the points of the plane around in a rigid fashion.</em>
A transformation is distance-preserving if the distance between the images of any two points and the distance between the two original points are equal.
If that's confusing, I get it; basically if you transform something, the points from the transformation are image points. Take the distance from a pair of image points, and take the distance from a pair of original points, and they should be the same for a <em>rigid </em>motion.
I keep emphasizing this b/c not all transformations preserve distance; a dilation can grow or shrink things. But if you didn't go over dilations, don't say nothin XD
9514 1404 393
Answer:
yes, yes, no, no
Step-by-step explanation:
An equation is linear if no term has a variable with an exponent other than 0 or 1. There can be no products of variables.
The equations with terms x³ or x² will not be linear.
(a, b) linear (yes)
(c, d) not linear (no)
<span>Hello :)
6(x+3)=(x+3)+(x+3)+(x+3)+(x+3)+(x+3)+(x+3)
Six times some number plus 3 is 42.</span>
Where’s the model? If it says choose a model, there should be a model
Y+4=10(x+3)
Y+4=10x+30
Y=10x+26
