Answer:
<em>V = 1,568</em>
Step-by-step explanation:
<u>The Volume of a Square Pyramid</u>
Given a square-based pyramid of base side a and height h, the volume can be calculated with the formula:
We are given a square pyramid with a base side a=14 ft but we're missing the height. It can be calculated by using the right triangle shown in the image attached below, whose hypotenuse is 25 ft and one leg is 7 ft
We use Pythagora's theorem:
Solving for h:
The height is h=24 ft. Now the volume is calculated:
V = 1,568
Bond Cost=Face Value×Percent
Bond cost=4,250×0.915=3,888.75
Factor the following:
12 x^4 - 42 x^3 - 90 x^2
Factor 6 x^2 out of 12 x^4 - 42 x^3 - 90 x^2:
6 x^2 (2 x^2 - 7 x - 15)
Factor the quadratic 2 x^2 - 7 x - 15. The coefficient of x^2 is 2 and the constant term is -15. The product of 2 and -15 is -30. The factors of -30 which sum to -7 are 3 and -10. So 2 x^2 - 7 x - 15 = 2 x^2 - 10 x + 3 x - 15 = x (2 x + 3) - 5 (2 x + 3):
6 x^2 x (2 x + 3) - 5 (2 x + 3)
Factor 2 x + 3 from x (2 x + 3) - 5 (2 x + 3):
Answer: 6 x^2 (2 x + 3) (x - 5)
Answer:
with what lol?
Step-by-step explanation:
