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3 years ago

HELPPP ME PLS!!!!!!!!!!!!

Mathematics

2 answers:

mestny [16]3 years ago

7 0

The correct answer is 1/3

alexgriva [62]3 years ago

3 0

1/3 divide it 18/6 is 3 21/7 is 3 24/8 is 3

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Can i have help soon please?

zavuch27 [327]

M<1 = 1/2(b-d)

answer is C. third choice

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3 years ago

Where are the asymptotes of f(x) = tan(4x − π) from x = 0 to x = π/ 2 ?

Aneli [31]

That answer was (B)................

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3 years ago

If y varies directly as x, and y is 20 when x is 4, what is the constant of variation for this relation?

Mekhanik [1.2K]

Answer:

[DATA EXPUNGED]

Step-by-step explanation:

[REDACTED]

7 0

3 years ago

Read 2 more answers

Evelyn wants to estimate the percentage of people who own a tablet computer she surveys 150 indvidals and finds that 120 own a t

igomit [66]

Answer:

The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%

Step-by-step explanation:

Confidence interval for the proportion of people who own a tablet:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 150, \pi = \frac{120}{150} = 0.8$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.576$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.7159$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.8841$

Percentage:

Multiply the proportion by 100.

0.7159*100 = 71.59%

0.8841*100 = 88.41%

The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%

8 0

3 years ago

Which expression is a difference of squares with a factor of 2x5?

Sedbober [7]

Answer:

${( \sqrt{3.5} })^{2} - {( \sqrt{1.5} )}^{2}$

Step-by-step explanation:

The difference of two squares identity is

${x}^{2} - {y}^{2} = (x - y)(x + y)$

When we let

$\sqrt{3.5}$

and

$\sqrt{1.5}$

, we get:

${( \sqrt{3.5} )}^{2} - {( \sqrt{1.5}) }^{2} = (3.5 - 1.5)(3.5 + 1.5)$

This will simplify to give us the required factors

${( \sqrt{3.5} )}^{2} - {( \sqrt{1.5}) }^{2} =2 \times 5$

7 0

3 years ago