If the town decreases at a rate of 8% per year, it would take 6 years.
100% - 8% = 92%
We would multiply each population per year by 0.92 as the town is decreasing in population by 8% per year
1st year: 18,000 • .92 = 16,560
2nd year: 16,560 • .92 = 15,235.2
3rd year: 15,235.2 • .92 = 14,016.384
4th year: 14,016.384 • .92 = 12,894.72
5th year: 12,894.72 • .92 = 11,863.1424
6th year: 11,863.1424 • .92 = 10,914.091
10,914 is less than 11,000 meaning it would take 6 years for the population to be fewer than 11,000 if the town is decreasing in population at a rate of 8% per year
Answer:
Step-by-step explanation:
Given
Required
Represent using an inequality and solve
Let the number of dollars be represented by n
<em>If 1 withdrawal is $20 bill</em>
<em>n withdrawals would be $20n bills</em>
The total withdrawal and the minimum balance must be less than or equal to the available balance.
So, this gives
Substitute values for each of these
Solving for n
Divide through by 20
But n can not be decimal because it represents number of dollar bills , which must always be an integer.
So, we round down the value of n
31/50
Showing the work
Rewrite the decimal number as a fraction with 1 in the denominator
0.62=0.62/1
Multiply to remove 2 decimal places. Here, you multiply top and bottom by 10^2=100
0.62/1*100/100=62/100
Find the Greatest Common Factor (GCF) of 62 and 100, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF=2,
62/2
_____=31/50
100/2
Therefore
X=31/50
In conclusion,
0.62=31/50
