Question

Identify and solve the inequality that represents how many $20 bills, n, you can withdraw from the account without going below the minimum balance.
your current balance is $230.00
minimum balance is $100

Answer 1

Answer:

$100 + 20n \leq 230$

$n \leq 6$

Step-by-step explanation:

Given

$Balance = \ 230.00$

$Minimum = \ 100$

$Withdrawal = \ 20\ each$

Required

Represent using an inequality and solve

Let the number of dollars be represented by n

If 1 withdrawal is $20 bill

n withdrawals would be $20n bills

The total withdrawal and the minimum balance must be less than or equal to the available balance.

So, this gives

$Minimum + Total\ Withdrawal \leq Available\ Balance$

Substitute values for each of these

$100 + 20n \leq 230$

Solving for n

$20n \leq 230 - 100$

$20n \leq 130$

Divide through by 20

$n \leq 6.5$

But n can not be decimal because it represents number of dollar bills , which must always be an integer.

So, we round down the value of n

$n \leq 6$