The order of these numbers is 2, to 3, to 17. hope this helps :))
Answer:
No, it cannot have a unique solution. Because there are more variables than equations, there must be at least one free variable. If the linear system is consistent and there is at least one free variable, the solution set contains infinitely many solutions. If the linear system is inconsistent, there is no solution.
Step-by-step explanation:
the questionnaire options are incomplete, however the given option is correct
We mark this option as correct because in a linear system of equations there can be more than one solution, since the components of the equations, that is, the variables are multiple, leaving free variables which generates more alternative solutions, however when there is no consistency there will be no solution
Step-by-step explanation:
If a variables varies jointly, we can just divide it by the other variables in relation to it.
For example, since p variables jointly as q and square of r, then

where k is a constant
First, let find k. Substitute p= 200
q= 2, and r=3.



Now, since we know our constant, let find p.

Q is 5, and r is 2.



b is the correct answer u got it
Select Is a Function or Is not a Function to correctly classify each relation.
<span><span>Title Is a Function Is not a Function</span><span><span><span><span>{<span><span>(<span>3, 7</span>)</span>,<span>(<span>3, 6</span>)</span>,<span>(<span>5, 4</span>)</span>,<span>(<span>4, 7</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>1, 5</span>)</span>,<span>(<span>3, 5</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>6, 4</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>2, 3</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>5, 8</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>0, 4</span>)</span>,<span>(<span>3, 2</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>6, 5</span>)</span></span>}</span></span>
</span></span></span>