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nataly862011 [7]
3 years ago
14

8-2y=3y-2 Help me please.

Mathematics
2 answers:
Ede4ka [16]3 years ago
7 0
This seems like a lot more work than it is, but here we go
Simplifying<span>8 + -2y = 3y + -2
 Reorder the terms: 8 + -2y = -2 + 3y
 Solving 8 + -2y = -2 + 3y Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right.
  Add '-3y' to each side of the equation. 8 + -2y + -3y = -2 + 3y + -3y Combine like terms: -2y + -3y = -5y 8 + -5y = -2 + 3y + -3y
 Combine like terms: 3y + -3y = 0 8 + -5y = -2 + 0 8 + -5y = -2 Add '-8' to each side of the equation. 8 + -8 + -5y = -2 + -8
 Combine like terms: 8 + -8 = 0 0 + -5y = -2 + -8 -5y = -2 + -8 Combine like terms: -2 + -8 = -10 -5y = -10
  Divide each side by '-5'. y = 2
 Simplifying y = 2</span>
Schach [20]3 years ago
4 0
Y equals 2. is that your question
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5 0
3 years ago
Will someone explain what i did wrong here?
tensa zangetsu [6.8K]

The actual inverse function is:

f^{-1}(x) = x^2 + 3

And the domain is [0, ∞).

<h3>Where is the mistake?</h3>

Remember that for a given function f(x) with a domain D and a range R.

For the inverse function, f⁻¹(x) the domain is R and the range is D.

Here, for the given function the domain is x ≥ 3 and the range is [0, ∞).

Then for the inverse function, which is:

f^{-1}(x) = x^2 + 3

(to check this, you must have that):

f^{-1}(f(x)) = x\\\\f(f^{-1}(x)) = x

The domain will be [0, ∞) and the range x ≥ 3

If you want to learn more about inverse functions:

brainly.com/question/14391067

#SPJ1

7 0
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