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alexira [117]
2 years ago
12

What is the answe ?????​

Mathematics
1 answer:
mestny [16]2 years ago
8 0

Answer:

1) The first option

2) -9, -7, 6, 8, 10

3) Rise by 10 degrees

Step-by-step explanation:

Ascending is from smallest to biggest therefore you start with the smallest negative number and end with biggest whole number.

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An 5kg object is 6 meters what is the potential energy
AVprozaik [17]

Potential Energy of an object of 5kg which is 6 meters in height is 294 Joules.

Step-by-step explanation:

We are given:

Mass = m = 5 kg

Height = h= 6 meters

Potential Energy = ?

The formula used to find Potential Energy is:

Potential\,\,Energy =mgh

where m is mass, g is gravitational field and h is height

Putting the given values of mass and height, and g=9.8 m/s^2

Potential Energy = 5*9.8*6\\Potential Energy = 294 Joules

So, Potential Energy of an object of 5kg which is 6 meters in height is 294 Joules.

Keywords: Potential Energy

Learn more about Potential Energy at:

  • brainly.com/question/6013189
  • brainly.com/question/9251988
  • brainly.com/question/1198647

#learnwithBrainly

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3 years ago
Solve the matrix equation for X.
Sedbober [7]

See the attached picture:

8 0
3 years ago
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Find 7.4 times the difference between 87 and 24​
AysviL [449]

Answer:

466.2

Step-by-step explanation:

8 0
2 years ago
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Which ist shows all the factors of 36?
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Answer:

the first one

1, 2, 3, 4, 6, 9, 12, 18, 36

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2 years ago
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What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12
Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, <u>2 is our minimum and 17 is our maximum.</u>

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5

<u>The median is 12.5.</u>

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6

<u>The first quartile is 6.</u>

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15

<u>The third quartile is 15.</u>

3 0
3 years ago
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