For this case we have the following functions:

We must find f (g (x)). So:

Finally we have to:

For the function to be defined the denominator must be different from 0. That is x different from -3.
Answer:
Option B
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The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at
(-1.5, -3.25).
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For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
The slope is 3, count from one point to o other. If you go from -2,0 up to -1,3 you go up 3 and over one so the slope is 3