First of all, you should know/notice that
![125=5^3](https://tex.z-dn.net/?f=125%3D5%5E3)
You should also know how negative exponents work:
![a^{-m}=\dfrac{1}{a^m}](https://tex.z-dn.net/?f=a%5E%7B-m%7D%3D%5Cdfrac%7B1%7D%7Ba%5Em%7D)
So, if you wanted
![5^x=125](https://tex.z-dn.net/?f=5%5Ex%3D125)
the answer would be x=3, but since you want 125 to be at the denominator, the answer is x=-3:
![5^{-3}=\dfrac{1}{5^3}=\dfrac{1}{125}](https://tex.z-dn.net/?f=5%5E%7B-3%7D%3D%5Cdfrac%7B1%7D%7B5%5E3%7D%3D%5Cdfrac%7B1%7D%7B125%7D)
Answer:
5
Step-by-step explanation:
- (4n+5)-n/20=1
- cross multiply:(4n+5)-n=20
- 4n+5=20+n
- 4n-n=20-5
- 3n=15
- Divide both sides by coefficient of n
- n=5
I'm pretty sure the answer is the last one:
6 x (40+2) = (6 x 40) + (6 x 2)
The 6 is distributed to the 40 and the 2
Answer:
10
Step-by-step explanation:
6^2+8^2=c^2 (c is the hypotenous)
100=c^2
c=10
Answer:
0 ≤ x ≤ 10
Step-by-step explanation:
The domain of f(x) is the set of values of x for which the function is defined. Here, the square root function is only defined for non-negative arguments, so we require ...
-x^2 +10x ≥ 0
x(10 -x) ≥ 0
The two factors in this product will both be positive only for values ...
0 ≤ x ≤ 10 . . . . the domain of f(x)