1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nekit [7.7K]
2 years ago
12

What is the standard deviation of the following set of data

Mathematics
1 answer:
Yuki888 [10]2 years ago
8 0

Answer:

7.79 to the nearest hundredth

Step-by-step explanation:

You might be interested in
Is this the right answer?
Ne4ueva [31]
Yes your answer is solved correctly
6 0
2 years ago
Factor the expression completely. 1/4x + 19/4
puteri [66]

Answer: i think it is... x = -19

8 0
2 years ago
QUICK!!<br><br> Which equation represents the relationship shown in the graph??
Dmitriy789 [7]

Answer:

y=1/2x

Step-by-step explanation:

Look at the graph, all you need is the first point.

Y is at 4 and X is at 2. We can divide y/x to get 4/2=1/2x

3 0
2 years ago
Read 2 more answers
Square of 96 by division method​
Serjik [45]

Answer:

the square of 96 by division method is

96  \times 96 = 9216

3 0
3 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
Other questions:
  • Please help me with the whole page. I need the answers and calculations please!
    11·1 answer
  • Brainliest + points!<br><br> please explain
    11·1 answer
  • Change 46/6 into a whole number
    6·1 answer
  • HELP ME PLEASE <br> solve the right triangle
    14·1 answer
  • If d is the standard deviation x, y, and z, what is the standard deviation of x + 5, y + 5, z + 5 ?
    11·1 answer
  • How many 5 Card hands have exactly 2 aces and 3 kings?
    8·1 answer
  • How many solutions does this equation have?<br> 7a + 5 (a + 3) = 8a + 4 (a + 2)
    13·1 answer
  • Please help me.<br><br>List the sides of MNP in ascending order:<br>m&lt; M = 15, m &lt; N= 75
    14·1 answer
  • Which of the following decimals is equal to 3 1/40 ? Select TWO that apply
    14·1 answer
  • Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!