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horrorfan [7]
2 years ago
10

These are confusing can anyone help with this?

Mathematics
1 answer:
mariarad [96]2 years ago
7 0

Answer:

3. B

Step-by-step explanation:

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Elana runs for 28 seconds and finishes at 250 meters .what is her velocity
Sophie [7]

Answer:

8.9m/s

Step-by-step explanation:

Time= 28s

Displacement= 250m

Velocity=?

Velocity (v) = displacement (d)/ Time (t)

V= 250/28

V=8.9m/s

OR YOU CAN APPROXIMATE IT

V=8.928

YOU CAN APPROXIMATE IT TO

V=8.93m/s

3 0
3 years ago
Find the area of the triangle when the coordinates are (2.5,4.5),(2,0),(9,2)
HACTEHA [7]
The area of the triangle is 14.625.... in order to find the area of a triangle just use this formula b×h÷2
6 0
3 years ago
I need help please please I appreciate it! ):
telo118 [61]

Answer:

!. Scale factor = 5

2. Scale factor = \frac{1}{5}

Step-by-step explanation:

scale = \frac{length in drawing}{actual length}

1. To increase the numbers, let the scale factor be \frac{5}{1} = 5. So that;

0.05 x 5 = 0.25

\frac{1}{2} x 5 = 0.5 x 5 = 2.50

7 x 5 = 35.00

13 x 5 = 65.00

25 x 5 = 125.00

102 x 5 = 510.00

2. To decrease the numbers, let the scale factor be \frac{1}{5}. So that;

0.05 x \frac{1}{5} = 0.01

\frac{1}{2} x \frac{1}{5} = 0.5 x \frac{1}{5} = 0.10

7 x \frac{1}{5} = 1.40

13 x \frac{1}{5} = 2.60

25 x \frac{1}{5} = 5.00

102 x \frac{1}{5} = 20.40

6 0
3 years ago
Two different families pay for entry into a water park.
icang [17]

Answer:

Adult ticket: $7

Child ticket: $2

Step-by-step explanation:

Set up a system of equations where a represents the cost of one adult ticket and c is the cost of one child ticket:

2a + 3c = 20

a + 4c = 15

Solve by elimination by multiplying the bottom equation by -2:

2a + 3c = 20

-2a -8c = -30

Add them together:

-5c = -10

c = 2

Now, we can plug in 2 as c to find the value of a:

2a + 3c = 20

2a + 3(2) = 20

2a + 6 = 20

2a = 14

a = 7

6 0
3 years ago
Integration of the following function
DerKrebs [107]

Answer: None of the above

Step-by-step explanation:

Given

\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}

d\bar{c}=\left (  -6x^{-2}+\frac{1}{6}\right )dx

Now, integrating both sides

\int d\bar{c}=\int \left (  -6x^{-2}+\frac{1}{6}\right )dx

\bar{c}=-6\frac{x^{-2+1}}{-2+1}+\frac{1}{6}x+k_1

\bar{c}=6x^{-1}+\frac{1}{6}x+k_1

6 0
3 years ago
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